When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g
He can eat his favorite cereal for 8 days because
125×8=1000 gm or 1 kg.
2.1 L
P1V1 = P2V2
P1 = 3.5 atm
V1 = 4.2 L
P2 = 7.0 atm
V2 = ?
Solve for V2 —> V2 = P1V1/P2
V2 = (3.5 atm)(4.2 L) / (7.0 atm) = 2.1 L
The smallest and the basic particle of a chemical element is said to be an atom. It is made up of three subatomic particles that is electrons, protons and neutrons. The neutrons and protons are present in the nucleus of an atom whereas electrons are present in the orbits around the nucleus of the atom. There are several shells in the orbital depending on the atomic number. The electrons which are present in the outermost shell are said to be valence electrons.
They can be determined by the electronic configuration of the element.
The atomic number of strontium, is 38. The electronic configuration of strontium, is:
From the electronic configuration it is clear that the outermost shell of strontium, is . So, the number of valence electrons in strontium, is 2.
Hence, there are 2 valence electrons in an atom of strontium ().
Symbol: Cl
Number of Neutrons: 18
Atomic Number: 17
Melting Point: -100.98 °C (172.17 K, -149.764 °F)
Number of Protons/Electrons: 17
Atomic Mass: 35.4527 amu