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Sever21 [200]
4 years ago
10

During which changes of state does the motion of the atoms decrease?

Chemistry
2 answers:
lesantik [10]4 years ago
4 0

freezing and condensation

Explanation:

The motion of the atoms decreases during freezing and condensation. These are phase changes that increases the molecular attraction between particles and forces them to come closer.

Freezing is a phase change from liquid to solid. It is usually achieved by removing heat from a substance and cooling it.

Condensation is a phase change from gases to liquid. .

Gases have the greatest motion because they have little to no attractive forces between them.

Phase changes from gas to solid to liquid generally reduces the motion of the atoms.

Learn more:

Phase change brainly.com/question/1875234

#learnwithBrainly

Thepotemich [5.8K]4 years ago
3 0

Answer:

FREEZING AND CONDENSATION

Explanation:

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A first-order reaction has a half-life of 20.0 minutes. Starting with 1.00 x 10^20 molecules
blsea [12.9K]

Answer:

E

Explanation:

100 minutes is   5 half lives  ( 100 min/20 min/half life)

         = (1/2 )^5

1 x 10^20    *    (1/2)^5 =   3.125 x10^18   molecules

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2 years ago
A sample of sand, 5cm in diameter and 10 cm long, was prepared at a porosity of 50% in a constant head apparatus. The total head
GarryVolchara [31]

Answer:

K = 2.037*10^{-3} m/s

V_s = 0.0122 \ m/s

Explanation:

Given that;

diameter (d) = 10cm/2 = 0.1m/2 = 0.05 m

length (l) = 10 cm = 0.1 m

porosity = 50%

height (h) = 30 cm = 0.3 m

time (t) = 5 s

volume (v) = 60 cm³ = 60 × 10⁻⁶ m³

Q (flow rate) = \frac{v}{t}

Q = \frac{60*10^{-6} m^3}{5}

Q = 12*10^{-6} m^3 /sec

From constant head method, we use the relation K = (\frac{Q*L}{A*h}) to determine the hydraulic conductivity ; we have:

K = \frac{12*10^{-6}*0.1}{\frac{\pi}{4}0.05^2*0.3}

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Seepage velocity V_s = \frac{velocity }{porosity}

where; velocity = K*i

=(2.037*10^{-3}*)(\frac{0.3}{0.1})

= 6.111*10^{-3} m/s

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8 0
4 years ago
When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu
olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

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Let's replace our values.

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1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC  = C = 0,50 J/gºC

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