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olga_2 [115]
3 years ago
14

Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks. A = B = C = D = E = F = G = H = A 3-colum

n table with 9 rows. Column 1 is labeled Time half-life cycles, n with entries Initial, 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Predicted radioactive atoms with entries 100, 50, 25, 13, 6, 3, 2, 1, 0. Column 3 is labeled Simulated radioactive atoms with entries 100, A, B, C, D, E, F, G, H.
Chemistry
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

A=  27

B=  16

C=  9

D=  4

E=  2

F=  2

G=  0

H= 0

Explanation:

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Sonbull [250]
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reactant:
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first you need to put probably an eight in front of the Carbon.
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should look like:
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7 0
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A liquid is cooled during an investigation causing it solidify.Which of the following most likely occurred? A.Absorption of heat
mojhsa [17]

Answer:

C. A physical change.

Explanation:

A liquid is cooled during an investigation causing it solidify.Which of the following most likely occurred?

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Which of the following has the most thermal energy? 500 mL water at 25°C 1.5 L water at 25°C 15 L water at 25°C
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6 0
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Calculate the wavelength of the photon that would be absorbed or emitted. Round your answer to 3 significant digits.
Flauer [41]

This is an incomplete question, the image for the given question is attached below.

Answer : The wavelength of photon would be absorbed, 3.06\times 10^{-7}m

Explanation :

From the given diagram of energy we conclude that,

Energy at ground state, A = 400 zJ

Energy of 2nd excited state, C = 1050 zJ

Now we have to calculate the energy of the photon.

E=E_c-E_A

E=(1050-400)zJ= 650zJ=650\times 10^{-21}J

Now we have to calculate the wavelength of the photon.

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

E = energy of photon = 650\times 10^{-21}J

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

650\times 10^{-21}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

\lambda=3.06\times 10^{-7}m

Therefore, the wavelength of photon would be absorbed, 3.06\times 10^{-7}m

5 0
3 years ago
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