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Nikolay [14]
3 years ago
5

As the pressure of a system changes, boiling points can change in what direction?

Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

If the pressure of the system increases then the boiling point will increase.

If the pressure of the system decreases then the boiling point will decrease. If there is no change in pressure then the boiling point will remain constant.

Explanation:

andrey2020 [161]3 years ago
4 0
Bhgdfghhhhhgg Hindubhhh
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0.2 mol of hydrocarbons undergo complete combustion to give 35.2 of carbon dioxide and 14.4g of water as the only product. What
MaRussiya [10]

Answer:

\rm C_4 H_8.

Explanation:

Look up the relative atomic mass of \rm C, \rm H, and \rm O on a modern periodic table:

  • \rm C: 12.011.
  • \rm H: 1.008.
  • \rm O: 15.999.

Calculate the molecular mass of \rm CO_2 and \rm H_2O:

M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1};

M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}.

Given the mass m of \rm CO_2 and \rm H_2O produced, calculate the number of moles of molecules that were produced:

\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO_2})} \approx 0.80\; \rm mol;

\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \approx 0.80\; \rm mol.

Calculate the number of moles of \rm C atoms and \rm H atoms in these \rm CO_2 and \rm H_2O molecules.

  • Each \rm CO_2 molecule contains one \rm C atom. Therefore, that 0.80\; \rm mol of \rm CO_2\! contains 0.80\; \rm mol\! of \rm C\! atoms.
  • Each \rm H_2O molecule contains two \rm H atoms. Therefore, that 0.80\; \rm mol of \rm H_2O\! contains 2 \times 0.80\; \rm mol = 1.60\; \rm mol of \rm H\! atoms.

The combustion reaction here include two reactants: the hydrocarbon and \rm O_2.

As the name suggests, hydrocarbons contain only \rm C atoms and \rm H atoms. On the other hand, \rm O_2 contains only \rm O atoms.

Therefore, all the \rm C and \rm H atoms in those \rm CO_2 and \rm H_2O molecules are from the unknown hydrocarbon. (With a similar logic, all the \rm O atoms in those combustion products are from \rm O_2.)

In other words, that 0.20\; \rm mol of this unknown hydrocarbon molecules contains:

  • 0.80\; \rm mol of \rm C atoms, and
  • 1.60\; \rm mol of \rm H atoms.

Hence, each of these hydrocarbon molecules would contain (0.80\; \rm mol) / (0.20\; \rm mol) = 4 carbon atoms and (1.60\; \rm mol) / (0.20\; \rm mol) = 8 hydrogen atoms.

The molecular formula of this hydrocarbon would be \rm C_{4} H_{8}.

6 0
3 years ago
If 3.00 g of titanium metal is reacted with 6.00 g of chlorine gas, Cl2, to form 7.7 g of titanium (IV) chloride in a combinatio
Crank

Ti + 2 Cl2 → TiCl4  

(3.00 g Ti) / (47.867 g Ti/mol) = 0.062674 mol Ti  

(6.00 g Cl2) / (70.9064 g Cl2/mol) = 0.084619 mol Cl2  

0.084619 mole of Cl2 would react completely with 0.084619 x (1/2) = 0.0423095 mole of Ti, but there is more Ti present than that, so Ti is in excess and Cl2 is the limiting reactant.  

(0.084619 mol Cl2) x (1 mol TiCl4 / 2 mol Cl2) x (189.679 g TiCl4/mol) = 8.025 g TiCl4 in theory  

(7.7 g) / (8.025 g) = 0.96 = 96% yield TiCl4

6 0
3 years ago
Read 2 more answers
wich answer choice contains organisms that are all prokaryotic. A. archaebacteria and bacteria B. bacteria and fungi C. protists
JulijaS [17]

Answer:

Explanation:

no

6 0
3 years ago
Pls help me!!!!!!!!!!!!!!!
ELEN [110]

Answer:

c

Explanation:

6 0
3 years ago
Read 2 more answers
Tough and malleable form of iron is
Alenkasestr [34]
The answer to your question is A. Wrought iron because amongst its other properties, wrought iron becomes soft at red heat, and can be easily be forged and forge welded.
4 0
4 years ago
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