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3 years ago

The active ingredient in toothpaste is sodium fluoride an anticavity agent. A 170. Gube

Chemistry

1 answer:

ivann1987 [24]3 years ago

6 0

There are <u>0.408 grams</u><u> </u>of sodium fluoride in the toothpaste.

Why?

We know that there is 0.24% of sodium floride in a 170 grams toothpaste tube. Since the only information related to the toothpaste is its mass, we can assume that the 0.24% (concentration) is referring to the mass percent, and we can calculate it using the following equation:

$MassPercent=\frac{MassSolute}{MasSolution}*100(percent)$

Now, substituting the given information and calculating, we have:

$MassPercent=\frac{MassSolute}{MasSolution}*100(percent)$

$\frac{MassPercent*MassSolution}{100}=MassSolute(NaF)\\\\MassSolute(NaF)=\frac{0.24*170g}{100}=0.408g$

We have that there are 0.408 grams of sodium fluoride in the toothpaste.

Have a nice day!

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