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3 years ago

What is kinematics . Give two examples

Physics

2 answers:

Wittaler [7]3 years ago

8 0

Answer:

kinematics explains the terms like acceleration, velocity, and position of the objects while in motion.

Some important parameters in kinematics are displacement, velocity, and time.

Explanation:

your welcome,can you give me the brainliest? plssss

thank me if it was correct for you too.

Varvara68 [4.7K]3 years ago

6 0

Answer:

<h3>Definition of Kinematics :- </h3>

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. ... An example model of bodies in a system is the gears in a vehicle's transmission.

<h3>Example of kinematics :- </h3><h3>The examples for kinematics are given below: -</h3>

i) Moving train and bus.
ii) Motion of a mass on inclined plane.
iii) Running water in the river.
iv) Falling water from a mountain peak.

Explanation:

<h3>Hope this helps you dear ✌️</h3><h2>Carry on learning !! </h2>

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When decreasing electromagnetic radiation there is a(n)_______relationship between wavelength and frequency and the greater the

IceJOKER [234]

Answer:

Inverse proportion, greater

Explanation:

The relation between wavelength (λ) and frequency (ν) is given by

$\nu = \frac{c}{\lambda }$

Where $c$ speed of light in vacuum.

We can see from this equation that wavelength and frequency are related inversely.

Now,

$E= h \nu$

Where 'E' is energy of electromagnetic radiation and 'h' is Planck's constant.

We can see from this equation that greater frequency (ν) will give greater electromagnetic radiation (E). As they are directly proportional.

Hence,

When decreasing electromagnetic radiation there is a(n) Inverse proportion relationship between wavelength and frequency and the greater the frequency, the greater energy the electromagnetic radiation has

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3 years ago

How to balance the equation NaNo3 + PbO & Pb(NO3)2 + Na2O

dedylja [7]

It would be "Double replacement".

Hope this helps!

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3 years ago

g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the

MrRa [10]

Answer:

Approximately $-1.58\; \rm rad \cdot s^{-2}$ .

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

$v^2 - u^2 = 2\, a\, x$ ,

where

$v$ is the final velocity of the moving object,
$u$ is the initial velocity of the moving object,
$a$ is the (linear) acceleration of the moving object, and
$x$ is the (linear) displacement of the object while its velocity changed from $u$ to $v$ .

The angular analogue of that equation will be:

$(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ , where

$\omega(\text{final})$ and $\omega(\text{initial})$ are the initial and final angular velocity of the rotating object,
$\alpha$ is the angular acceleration of the moving object, and
$\theta$ is the angular displacement of the object while its angular velocity changed from $\omega(\text{initial})$ to $\omega(\text{final})$ .

For this object:

$\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}$ , whereas
$\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}$ .

The question is asking for an angular acceleration with the unit $\rm rad \cdot s^{-1}$ . However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

$\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}$ .

Rearrange the equation $(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ and solve for $\alpha$ :

$\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}$ .

7 0

3 years ago

Help please, i need the claim, evidence and reasoning

My name is Ann [436]

Answer: at night when the full moon is there the tide begans to appear higher

Explanation:

4 0

3 years ago

A point charge q1 is at the center of a sphere of radius 20 cm. Another point charge q2 = 10 nC is located at a distance r = 10

jok3333 [9.3K]

Answer:

q₁ = -2.92 nC

Explanation:

Given;

first point charge, q₁ = ?

second point charge, q₂ = 10 nC

net flux through the surface of the sphere, Φ = 800 N.m²/C

According to Gauss’s law, the flux through any closed surface (Gaussian surface), is equal to the net charge enclosed divided by the permittivity of free space.

$\phi = \frac{q_{enc.}}{\epsilon_o}$

where;

Φ is net flux

$q_{enc.}$ net charge enclosed

ε₀ is permittivity of free space.

$q_{enc.}$ = Φε₀

= 800 x 8.85 x 10⁻¹²

= 7.08 x 10⁻⁹ C

$q_{enc.}$ = 7.08 nC

q₁ + q₂ = $q_{enc.}$

q₁ = $q_{enc.}$ - q₂

q₁ = 7.08nC - 10 nC

q₁ = -2.92 nC

4 0

3 years ago

What is kinematics . Give two examples​

What is kinematics . Give two examples