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3 years ago

The air in a cool region underneath cloud cover will have _____ a region with no cloud cover.

Physics

2 answers:

Slav-nsk [51]3 years ago

7 0

<u>Answer:</u>

The air is a <u>homogeneous mixture of gases</u> that make up the Earth's atmosphere, which remain around the planet by the attraction force of gravity.

Its properties changes with the altitude, the pressure, the temperature and the density. For example, there is a relation that is <u>inversely proportional</u> between the temperature and the air density.

<h2>When the temperature decreases the density increases. </h2>

Therefore, the air in a cool region of the atmosphere will be denser than the air in a hot region of the atmosphere.

In other words:

<h2>The air in a cool region underneath cloud cover will have <em><u>a higher density than</u></em> a region with no cloud cover </h2><h2> </h2>

Aleksandr-060686 [28]3 years ago

5 0

The air in a cool region underneath cloud cover will have a higher density than a region with no cloud cover. A region with no cloud cover has warmer air than the surrounding air, it becomes less dense and begins to rise, drawing more air in underneath.

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Which graph shows the relationship between temperature, X, and kinetic energy, Y?

strojnjashka [21]

Answer: see the graph attached (straight line, passing through the origin and positive slope).

Justification:

1) Kinetic energy and temperature are in direct proportion. That means:

i) Being kinetic energy y and temperature x: y α x

ii) That implies: y = kx,where k is the constant of proportionality.

iii) The graph is a line that passes through the origin and has positive slope k (k = y / x).

2) The proportional relationship between kinetic energy (KE) and temperature (T) is shown by the Boltzman law, which states:

Average KE = [3 / 2] KT, where K is Boltzman's constant, whose graph is of the form shown in the figure attached.

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3 years ago

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William Gilbert used a terella in an attempt to explain _____.

Alex787 [66]

Answer:

why compasses point towards the north and south poles of the earth.

Explanation:

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6 0

2 years ago

The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg

kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

$\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\$

From the graph;

$\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m$

The change in the momentum is;

$\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \ N.s$

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

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6 0

1 year ago

330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°

Olenka [21]

The final temperature of the system is 32.5°
we know, H = mcT
where, H = Heat content of the body
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry

The net heat remains constant i.e.
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x $\frac{900}{4200}$ x (T - 10)

⇒ 14,850 - 330T = 183.21T - 1832

⇒ - 513.21 T = - 16682

or T = 32.5°

3 0

2 years ago

In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 1850 J of work is done on the gas

hammer [34]

Answer:

The value of change in internal energy of the gas = + 1850 J

Explanation:

Work done on the gas (W) = - 1850 J

Negative sign is due to work done on the system.

From the first law we know that Q = Δ U + W ------------- (1)

Where Q = Heat transfer to the gas

Δ U = Change in internal energy of the gas

W = work done on the gas

Since it is adiabatic compression of the gas so heat transfer to the gas is zero.

⇒ Q = 0

So from equation (1)

⇒ Δ U = - W ----------------- (2)

⇒ W = - 1850 J (Given)

⇒ Δ U = - (- 1850)

⇒ Δ U = + 1850 J

This is the value of change in internal energy of the gas.

7 0

3 years ago