2 years ago

5 ways in which friction can be useful

Physics

2 answers:

Natasha2012 [34]2 years ago

5 0

Answer:

Slowing you down?

Heat?

Explanation:

notka56 [123]2 years ago

3 0

to heat different things

to be able to put stuff on something with friction and it not fall

to create static electricty ]

you would really help me if you put brainlest

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A car is stopped at a traffic light. When the light turns green, the car starts from rest with an acceleration of 2.5 m/s2 . Als

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Answer:

a) f = 453.3Hz

b) f = 443.1Hz

c) f = 420Hz

Explanation:

First of all we need to know the positions and velocities of both vehicles.

For the car:

Xc(-5) = 0m; Vc(-5) = 0m/s

$Xc(5) = 2.5*5^2/2=31.25m$ ; Vc(5)=2.5*5 = 12.5m/s

$Xc(10)=2.5*10^2/2=125m$ ; Vc(10)=2.5*10=25m/s

For the truck:

Xt(-5)=10*(-5) = -50m; Vt(5)=10m/s

Xt(5)=10*5 = 50m; Vt(5)=10m/s

Xt(10)=10*10=100m; Vt(10)=10m/s

Now for part a) t=-5s. The truck is behind the car, so:

$f=\frac{C}{C-Vt}*fo = 453.3Hz$

Now for part b) t=5s. The car is behind the truck, so:

$f=\frac{C+Vc}{C+Vt}*fo = 443.1Hz$

Now for part b) t=10s. The truck is behind the car, so:

$f=\frac{C-Vc}{C-Vt}*fo = 420Hz$

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The theory that attitudes will be formed and changed according to one’s actual behaviors is the __________ theory. A. learning B

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A is the answer

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An object with a mass of 1.5kg changes its velocity from +15m/s to +22 during a time interval of 3.5 seconds. What Impulse was d

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A factory emits pollutants at a rate of 25 g/s. The factory is located between two mountain ranges resulting in an effective val

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Answer:

$1.25\ \mu\text{g/m}^3$

Explanation:

v = Velocity of the breeze = 4 m/s

w = Width of the valley = 5000 m

h = Height of the valley = 1000 m

Volumetric flow rate is given by

$\dot{V}=vwh\\\Rightarrow \dot{V}=4\times 5000\times 1000\\\Rightarrow \dot{V}=2\times10^{7}\ \text{m}^3/\text{s}$

$\dot{m}$ = Mass flow rate of pollutant = 25 g/s = $25\times 10^6\ \mu\text{g/s}$

Concentration is given by

$C=\dfrac{\dot{m}}{\dot{V}}\\\Rightarrow C=\dfrac{25\times 10^6}{2\times 10^7}\\\Rightarrow C=1.25\ \mu\text{g/m}^3$

The steady state concentration of pollutants in the valley, is $1.25\ \mu\text{g/m}^3$ .

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