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hjlf
3 years ago
11

Which cloud type consists of globular cloud masses with a cauliflower structure?

Physics
2 answers:
Brrunno [24]3 years ago
7 0

Answer:

Cumulus has the cauliflower structure.

inysia [295]3 years ago
6 0

Answer:

Cumulus cloud is the correct answer.

Can i get brainliest please? Thanks!

Explanation:

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I would say Honesty, Loyalty, and Trust

Explanation:

well, thats just in my opinion and other people have their own preferences

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How does sound intensity differ from loudness?
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Loudness<span> refers to how loud or soft a </span>sound<span> seems to a listener. The </span>loudness<span> of </span>sound is<span> determined, in turn, by the </span>intensity<span>, or amount of energy, in </span>sound<span> waves. The unit of </span>intensity is<span> the decibel (dB). As decibel levels get higher, </span>sound<span> waves have greater </span>intensity<span> and </span>sounds are<span> louder.</span>
3 0
3 years ago
If the star Alpha Centauri were moved to a distance 10 times farther than it is now, its parallax angle would
steposvetlana [31]

Answer:

B. get smaller

Explanation:

The parallax angle of a star measured with respect to the Earth is inversely proportional to the distance of the star from the Earth:

\theta = \frac{1}{d}

where

\theta is the parallax angle, measured in arcsec

d is the distance between the star and the Earth, measured in parsec

Therefore, if the star Alpha Centauri is moved farther from Earth, then d increases, and therefore the parallax angle will get smaller.

3 0
3 years ago
A car initially traveling at 27.7 m/s undergoes a constant negative acceleration of magnitude 2.00 m/s2 after its brakes are app
lys-0071 [83]

The car's velocity at time <em>t</em> is given by

v=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t

It comes to a stop when <em>v</em> = 0, which happens when

0=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t\implies t=13.85\,\mathrm s

or after about 13.9 s.

In this time, the car travels a distance <em>x</em> given by

x=\left(27.7\dfrac{\rm m}{\mathrm s}\right)(13.85\,\mathrm s)+\dfrac12\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)(13.85\,\mathrm s)^2=191.823\,\mathrm m

or about 192 m.

In one complete revolution, each tire covers a distance equal to its circumference,

2\pi(0.340\,\mathrm m)\approx2.13628\,\mathrm m

or about 2.14 m.

This means each tire will complete approximately 192/2.14 ≈ 90 revolutions.

8 0
3 years ago
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