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3 years ago

Which cloud type consists of globular cloud masses with a cauliflower structure?

Physics

2 answers:

Brrunno [24]3 years ago

7 0

Answer:

Cumulus has the cauliflower structure.

inysia [295]3 years ago

6 0

Answer:

Cumulus cloud is the correct answer.

Can i get brainliest please? Thanks!

Explanation:

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Explanation:

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How does sound intensity differ from loudness?

Alchen [17]

Loudness refers to how loud or soft a sound seems to a listener. The loudness of sound is determined, in turn, by the intensity, or amount of energy, in sound waves. The unit of intensity is the decibel (dB). As decibel levels get higher, sound waves have greater intensity and sounds are louder.

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3 years ago

If the star Alpha Centauri were moved to a distance 10 times farther than it is now, its parallax angle would

steposvetlana [31]

Answer:

B. get smaller

Explanation:

The parallax angle of a star measured with respect to the Earth is inversely proportional to the distance of the star from the Earth:

$\theta = \frac{1}{d}$

where

$\theta$ is the parallax angle, measured in arcsec

d is the distance between the star and the Earth, measured in parsec

Therefore, if the star Alpha Centauri is moved farther from Earth, then d increases, and therefore the parallax angle will get smaller.

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3 years ago

A car initially traveling at 27.7 m/s undergoes a constant negative acceleration of magnitude 2.00 m/s2 after its brakes are app

lys-0071 [83]

The car's velocity at time t is given by

$v=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t$

It comes to a stop when v = 0, which happens when

$0=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t\implies t=13.85\,\mathrm s$

or after about 13.9 s.

In this time, the car travels a distance x given by

$x=\left(27.7\dfrac{\rm m}{\mathrm s}\right)(13.85\,\mathrm s)+\dfrac12\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)(13.85\,\mathrm s)^2=191.823\,\mathrm m$

or about 192 m.

In one complete revolution, each tire covers a distance equal to its circumference,

$2\pi(0.340\,\mathrm m)\approx2.13628\,\mathrm m$

or about 2.14 m.

This means each tire will complete approximately 192/2.14 ≈ 90 revolutions.

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3 years ago