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Nikitich [7]
3 years ago
14

A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity

of 1.65 m/s. After the collision, the 8 kg car continues forward with a velocity of 0.5 m/s. What is the new velocity of the 5.28 kg car after the collision?
Physics
1 answer:
Margaret [11]3 years ago
3 0
This is a case of elastic collision.
The equation is m1v1i+m2v2i=m1v1f+m2v2f
Substituting we get:
(8)(5)+(5.28)(-1.65)=(8)(0.5)+(5.28)(v2f)
V2f=5.168m/s
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k0ka [10]
<span> D. orbital rendezvous</span>
6 0
3 years ago
A raft of mass 199 kg carries two swimmers of mass 52 kg and 70 kg. The raft is initially floating at rest. The two swimmers sim
Minchanka [31]

To solve this problem we will apply the concept related to the conservation of the Momentum. We will then start considering that the amount of initial momentum must be equal to the amount of final momentum. Considering that all the objects at the initial moment have the same initial velocity (Zero, since they start from rest) the final moment will be equivalent to the multiplication of the mass of each object by the velocity of each object, so

Initial Momentum = Final Momentum

(m_B+m_1+m_2)v_i = m_1v_1+m_2v_2+m_Bv_B

Here,

m_B =  mass of Raft

m_1 = Mass of swimmers 1

m_2 = Mass of swimmers 2

v_i = Initial velocity (of the three objects)

v_B = Velocity of Raft

Replacing,

(199+52+70)*0 = (52)(4)+(70)(-4)+199v_B

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vB = \frac{72}{199}

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Therefore the velocity the rarft start to move is 0.3618m/s

5 0
4 years ago
The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh
frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

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Determine the weight of crab body

We need to calculate the value of proportional constant

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y=kx^{1.25}

k=\dfrac{y}{x^{1.25}}

Put the value into the formula

k=\dfrac{1.8}{1.1^{1.25}}

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We need to calculate the crab weight

y=kx^{1.25}

Here, x = 0.85 g

Put the value into the formula

y=1.5978\times(0.85)^{1.25}

y=1.3040\ gram

Hence, The weight of body is 1.3040 gram.

7 0
4 years ago
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snow_lady [41]
The wire vibrates back and forth between the poles of the magnet.
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