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kondor19780726 [428]
2 years ago
7

Balance the following chemical equations:

Chemistry
1 answer:
tamaranim1 [39]2 years ago
3 0

Answer:

Explanation

=============

One

=============

Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + H2O

Focus on the NO3. This is an odd problem and you usually do not focus on the complex ion. But this one works easiest if you do.

The problem now is going to be the oxygens. There are 2 with the Calcium and only 1 free one going to the water. (The NO3 has been taken care of in the last step).

Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O

Count the atoms. I think this equation is balanced.

atom                      Left              Right         Result

Ca                            1                    1               Balanced

O                              8                   8              Balanced

H                              2 + 2              2*2         Balanced

N                               2                    2            Balanced

===========

Two

===========

CH4 + O2====>  CO2 + H2O

Start with the hydrogens.

The right side requires a 2

CH4 + O2 ===>  CO2 + 2H2O

Now look at the oxygens. There are 4 on the right. and only 2 on the left. You need to multiply O2 by 2

CH4 + 2O2 ===>  CO2 + 2H2O

Each side has 1 Carbon 4 hydrogens and 4 oxygens. The equation is balanced.

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A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
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2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

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14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

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92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
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To calculate the number of moles, we use the equation:

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