Answer:
Explanation:
Hello!
In this case, for the separation of the benzene-toluene mixture, we can use the following mole balances including the given mole fraction at each stream per species:
That can be solved by using a solver for P1 (benzene-rich flow) and P2 (toluene-rich flow):
Best regards!
Answer:
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)
Explanation:
Rubidium has a more negative reduction potential (-2.98 V) compared to strontium (-2.89 V).
Hence, in a redox reaction involving rubidium and strontium, rubidium will be oxidized while strontium is reduced.
The balanced redox reaction equation is obtained from;
Oxidation half equation;
2Rb(s) ---->2Rb^+(aq) + 2e
Reduction half equation;
Sr^2+(aq) + 2e ----> Sr(s)
Overall reaction equation;
2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)
Answer:
Salt particles will diffuse and towards where it is less that is left !!
so your answer is A !! left through diffusion !!
Explanation:
Answer:
2.951 × 10⁻⁵ M
Explanation:
Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.
HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)
Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.
pH = -log [H₃O⁺]
[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M
