Answer:Silicon is neither metal nor non-metal; it's a metalloid, an element that falls somewhere between the two. The category of metalloid is something of a gray area, with no firm definition of what fits the bill, but metalloids generally have properties of both metals and non-metals.
Explanation:
Answers are:
2. It pushes on all objects that are on Earth’s surface.
3. It can be measured in atmospheres or kilopascals.
Barometric pressure (atmospheric pressure), is the pressure within the atmosphere of Earth
Atmospheric pressure decreases with increasing height, because there are fewer air molecules above a given object.
Barometer is an instrument used in meteorology to measure atmospheric pressure.
Atmospheric pressure (atm) is the force per unit area by the weight of air above that point.
Kilopascal (kPa) is a metric system pressure unit and equals to 1000 force of newton per square meter.
Atmospheric pressure results from molecular collisions of atmospheric gases.
Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
Solubility is the maximum amount of a substance that will dissolve in a given amount of solvent at a specific temperature. There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.
<span>A 50 kg student runs up a flight of stairs that is 6 m high. How much work is done? 3000 J. Calculate the work done when a force of 1 N moves a book 2 m. 2 J .... 200 W, 100 W. Calculate the power expended when a 500. N barbell is lifted 2.2 m in 2.0 seconds. 550 W. energy. the property of an object or system that ...</span>
