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Lelu [443]
4 years ago
14

Humans and other complex organisms have a hierarchical system of organization. Which of the following statements is true regardi

ng this system of organization?
A.Atoms are made up of cells
B.Organs are made up of organ systems
C.Cells are made of tissues
D.Organs are made of tissues
Chemistry
1 answer:
Marianna [84]4 years ago
4 0
The answer is D.Organs are made of tissues
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Why is rain water always somewhat acidic?
Olin [163]
A.Because the Carbon dioxide in the air mixes it to form carbonic acid
3 0
4 years ago
Read 2 more answers
For the reaction:
Zepler [3.9K]

Answer:

The equilibrium constant for CO now

= 0.212 M

For H₂O

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

Explanation:

The chemical equation for the reaction is:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

The ICE Table for this reaction can be represented as follows:

                   CO(g)      +   H2O(g)   ⇌    CO2(g)   +     H2(g)

Initial            0.5                0.5                   -                      -

Change        -x                   -x                      + x                + x

Equilibrium   0.5 -x           0.5 - x

The equilibrium constantK_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}

K_c = \dfrac{[x]^2}{[0.5-x]^2}

where; K_c = 1.845

1.845 = \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}^2

\sqrt{1.845}= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}

1.3583= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}

1.3583 (0.5-x) = x

0.67915  - 1.3583x = x

0.67915  = x +  1.3583x

0.67915 = 2.3583x

x = 0.67915/2.3583

x = 0.2880

The equilibrium constant for CO now = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For H₂O = 0.5 - x

= 0.5 -  0.2880

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

3 0
3 years ago
What mass of CaCl2 (in g ) should the chemist use?
solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is  required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M *  6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles  * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

Learn more about solute:brainly.com/question/7932885

#SPJ1

Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

3 0
1 year ago
How long is a wave traveling at 120 m/s if it has a frequency of 30 Hz?
julia-pushkina [17]

Answer:

4 m

Explanation:

6 0
3 years ago
Please help! Consider the following reaction: 3H2S (g) + 3O2 (g)  2 SO2 (g) + 2H2O (g) If O2 was the excess reagent, 4.15 mol o
iren [92.7K]

Answer:

91.8 %

Explanation:

Data given:

Amount of H₂S = 4.15 mol

Amount of water (H₂O) = 68.55 g

Amount of oxygen O₂ = in excess

Percent yield of reaction water (H₂O) of water = ?

Reaction Given:

          2H₂S (g) + 3O₂ (g) ----------> 2SO₂ (g) + 2H₂O (g)

Solution:

First we look for the theoretical yield by looking in the reaction

          2H₂S (g) + 3O₂ (g) ----------> 2SO₂ (g) + 2H₂O (g)

As oxygen is in the excess so only H₂S amount act as limiting reagent.

           2H₂S (g) + 3O₂ (g) ----------> 2SO₂ (g) + 2H₂O (g)

             2 mol                                                       2 mol

to convert amount of H₂O from moles to grams

           mass in grams = no. of moles x molar mass

Molar Mass of H₂O = 2(1) + 16 = 18 g/mol

Put values in above equation

          mass in grams = 2 mol x 18 g/mol

          mass in grams = 36 g

So,

             3H₂S (g) + 3O₂ (g) ----------> 2SO₂ (g) + 2H₂O (g)

             2 mol                                                         36 g

As from the reaction it is clear that 2 mole of H₂S gives 36g H₂O then 4.15 mole will give how many grams of water

Apply unity formula

                         2 mol of H₂S ≅ 36 g of H₂O

                         4.15 mol of H₂S ≅ X g of H₂O

Do cross multiplication

                X g of H₂O =  36 g x 4.15 mol / 2 mol

                X g of H₂O =  74.7 g

So theoretical yield =  74.7 g of H₂O

Formula used for percent yield

            percent yield = actual yield / theoretical yield x 100

Put values in above equation

           percent yield = 68.55 g / 74.7 g x 100

           percent yield = 91.8 %

***Note

For SO₂ it is important to have actual yield. and implement same work.

6 0
4 years ago
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