Answer:
<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>
Explanation:
<u>Electric Power in a Resistor</u>
Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:
V = R.I
The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:
Solving the first equation for I:
Substituting in the second equation:
Simplifying:
Solving for V:
The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:
V = 4.85 V
The maximum voltage that can be applied without damaging the resistor is 4.85 V
The formation of bubbles, a change in color, and the formation of a precipitate (1, 3, & 5) are all indicators that a chemical reaction is occurring.
Answer:
The answer to your question is : vf = 15.18 m/s
Explanation:
Data
vo = 24 m/s
d = 120 m
vf = ? when d = 60.0 m
Formula
vf² = vo² + 2ad
For d =100m
a = (vf² - vo²) / 2d
a = (0 -24²) / 2(100)
a = -576/200
a = 2.88 m/s²
Now, when d = 60
vf² = (24)² - 2(2.88)(60)
vf² = 576 - 345.6
vf² = 230.4
vf = 15.18 m/s
Answer:
Time, t = 8 seconds
Explanation:
An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :
We need to find the time when the object will hit the ground. When it will hit the ground, h = 0
So,
On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.
Answer:
1.so that we won't do any mistakes and won't have injuries.
Explanation:
yes.
because it is a right thing to use correct tools for correct work.
