Answer:
104.4km
Explanation:
Projectile motion occurs when object is launched into air and allowed to fall freely under the influence of gravity.
Maximum height reached by the object is expressed as;
H = u²sin²(theta)/2g where;
u is the initial velocity = 1.445km/s
u = 1445m/s since 1000m is equivalent to 1km
theta is the angle of launch
g is the acceleration due to gravity = 10m/s²
theta = 90° (since object is launched vertically)
Substituting the values in the formula we have;
H = 1445²(sin90°)²/2(10)
H = 1445²/20
H = 104,401.25m
H = 104.4km
The the maximum height reached by the capsule is 104.4km