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andrew-mc [135]
3 years ago
11

How os the 2 in the number 582 different from the 2 in the number 528

Mathematics
2 answers:
Mkey [24]3 years ago
8 0
In 582 the 2 is in the ones place
In 528 the 2 is in the tens place
stealth61 [152]3 years ago
8 0
The 2 in 582 is meant to be as a single number / in the ones place
the 2 in 528 is meant to be as a tenth  as twenty and not a two like it is in the other number
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convert the following logarithmic equation to the equivalent exponential equation. Use the caret (^) to enter exponents. y=ln x
GarryVolchara [31]
1. To solve this problem, you need to remember that an exponential function has the following form:
 
 f(x)=a^x
 
 "a" is the base and "x" is the exponent.
 
 2. It is important to know that the logarithmic functions  and the exponential functionsare inverse. Then, you have:
 
 <span>y=ln x
</span> e^y=e^(lnx)
<span> e^y=x
 
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5 0
3 years ago
PLS HELP IM DESPARATE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jeka57 [31]

Answer:

x=30°

2x=60°

Step-by-step explanation:

Value of x°=x°/(2x°+x°)×90°

= 1/3×90°

=30°

Value of 2x°=30°×2

=60°

4 0
3 years ago
Read 2 more answers
-73 greater than or equal to 15 + 11x
Alecsey [184]
-73 ≥ 15 + 11x 
so the first thing you should do is to add -15 on both sides of the equation so you will have:
-73 -15 ≥ 11x 
- 88 ≥ 11x 
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-88/11 ≥ x or -8 ≥ x :)))
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5 0
3 years ago
Read 2 more answers
Pls help! will give brainliest
IrinaVladis [17]

7) D -80

8) C -3.3

9) A 127.6

6 0
3 years ago
a radioactive sample contains 3.00 g of pure 11c, which has a half-life of 20.4 min. (a) how many moles of 11c are present initi
sveta [45]

The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the number of mole of pure 11C. Detail below:

<h3>How to determine the mole of 11C</h3>

From the question given, the following data were obtained:

  • Molar mass of 11C = 11 g/mol
  • Mass of 11C = 3 g
  • Mole of 11C =?

Mole = mass / molar mass

Mole = 3 / 11

Mole = 0.2727 mole

Therefore, the number of mole of pure 11C initially present is 0.2727 mole

Learn more about mole:

brainly.com/question/13314627

#SPJ4

8 0
2 years ago
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