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erica [24]
3 years ago
8

Before Mendeleev, Newland observed a distinct pattern in the elements and proposed the law of octaves. What were his conclusions

?
Chemistry
2 answers:
zhuklara [117]3 years ago
5 0
WHILE ARRANGING THE ELEMENTS, NEWLAND OBSERVED THAT ORDER HE SET WERE LIKE NOTES REPRESENTED AS THE SIGNS,THAT IS, EVERY FIRST NOTE IS EQUAL TO THE EIGHT ELEMENT, BUT HE COULD FIND ONLY 58 ELEMENTS THAT WERE CORRECTLY ORDERED IN HIS TABLE
maksim [4K]3 years ago
4 0

Explanation:

Hello! We will answer this!

Newland was an English analytical chemist who ordered the elements of the periodic table according to their atomic masses.

He stated the law of the octaves, where he realized that every eight elements, the characteristics are similar.

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C

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What determines the length of each period in the periodic table?
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The number of electrons that can occupy the sub levels being filled by that period
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In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
You observe that the hair on your head stands up when a charged balloon is brought near without touching your head. Based on thi
Ymorist [56]

Answer:

You reverse the first and second steps.

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The balloon won't do anything until it is charged.

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Miller's classic experiment demonstrated that a discharge of sparks through a mixture of gases could result in the formation of
Diano4ka-milaya [45]

Answer:

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Explanation:

According to my research on Stanley Millers Experiment, I can say that based on the information provided within the question Miller did not use Oxygen as one of the gases in his experiment. On his 1953 experiment the gases used were methane, ammonia, and hydrogen

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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