Answer:
Explanation:
Given
mass of wheel m=13 kg
radius of wheel=1.8 m
N=469 rev/min
![\omega =\frac{2\pi \times 469}{60}=49.11 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7B2%5Cpi%20%5Ctimes%20469%7D%7B60%7D%3D49.11%20rad%2Fs)
t=16 s
Angular deceleration in 16 s
![\omega =\omega _0+\alpha \cdot t](https://tex.z-dn.net/?f=%5Comega%20%3D%5Comega%20_0%2B%5Calpha%20%5Ccdot%20t)
![\alpha =\frac{\omega }{t}=\frac{49.11}{16}=3.069 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7B%5Comega%20%7D%7Bt%7D%3D%5Cfrac%7B49.11%7D%7B16%7D%3D3.069%20rad%2Fs%5E2)
Moment of Inertia ![I=mr^2=13\times 1.8^2=42.12 kg-m^2](https://tex.z-dn.net/?f=I%3Dmr%5E2%3D13%5Ctimes%201.8%5E2%3D42.12%20kg-m%5E2)
Change in kinetic energy =Work done
Change in kinetic Energy![=\frac{I\omega ^2}{2}-\frac{I\omega _0^2}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BI%5Comega%20%5E2%7D%7B2%7D-%5Cfrac%7BI%5Comega%20_0%5E2%7D%7B2%7D)
![\Delta KE=\frac{42.12\times 49.11^2}{2}=50,792.34 J](https://tex.z-dn.net/?f=%5CDelta%20KE%3D%5Cfrac%7B42.12%5Ctimes%2049.11%5E2%7D%7B2%7D%3D50%2C792.34%20J)
(a)Work done =50.79 kJ
(b)Average Power
![P_{avg}=\frac{E}{t}=\frac{50.792}{16}=3.174 kW](https://tex.z-dn.net/?f=P_%7Bavg%7D%3D%5Cfrac%7BE%7D%7Bt%7D%3D%5Cfrac%7B50.792%7D%7B16%7D%3D3.174%20kW)
Answer:
look at explanation
Explanation:
If heat rises, then why is it so cold at the top of a mountain? Heat does indeed rise. More specifically, a mass of air that is warmer than the air around it expands, becomes less dense, and will therefore float atop the cooler air. ... So when warm air rises, it cools off.
S s. S s abbs s sbsbs z sbs
Answer:
work done is -150 kJ
Explanation:
given data
volume v1 = 2 m³
pressure p1 = 100 kPa
pressure p2 = 200 kPa
internal energy = 10 kJ
heat is transferred = 150 kJ
solution
we know from 1st law of thermodynamic is
Q = du +W ............1
put here value and we get
-140 = 10 + W
W = -150 kJ
as here work done is -ve so we can say work is being done on system