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3 years ago

1. Sound waves produced by a vibrating object are _____.

2 answers:

6 0

1. Sound waves produced by a vibrating object are compressional waves.
2. Loudness is the human perception of sound wave intensity.
3. The process of detecting objects by bouncing sounds off them is called echolocation.

Dominik [7]3 years ago

4 0

Sound waves produced by a vibrating object are _____.

Answer: 1) Sound waves produced by a vibrating object are compressional waves. The reason being that the matter in the medium moves back and forth in the same direction that it travels. 2) Loudness is the human perception of sound wave intensity. 3) The process of detecting objects by bouncing sounds off them is called echolocation. It is also called bio sonar and animals like bats use it to detect objects near them.

I hope it helps, Regards.

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11. A plow pushes 100 kg of snow with 300 N of force. How much is the pile of snow<br> accelerated?

Fed [463]

Answer:

Explanation:

This is an application of Newton's second Law.

Formula

F = m * a

F = 300 N

m = 100 kg

a = ?

F = m * a

300N = 100 kg * a Divide by 100

300N/100kg = a

a = 3 m/sec^2

3 0

2 years ago

A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.

charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0

3 years ago

A toy gun uses a spring to project a 4.5-g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the gu

marishachu [46]

Answer:

1.93 m/s

Explanation:

Parameters given:

Mass = 4.5g = 0.0045kg

Spring constant = 8.0 N/m

Length of barrel = 13 cm = 0.013m

Frictional force = 0.035N

Compression = 5.8 cm = 0.058m

First, we find the P. E. stored in the spring:

P. E. = ½*k*x²

P. E. = ½ * 8 * 0.058² = 0.013J

Then, we find the work done by the frictional force while the sphere is leaving the barrel of the gun:

Work = Force * distance

The distance here is the length of the barrel.

Work = 0.035 * 0.13 = 0.0046 J

The kinetic energy of the sphere can now be found:

K. E. = P. E. - Work done

K. E. = 0.013 - 0.0046 = 0.0084J

We can now find the speed using the formula for K. E.:

K. E. = ½*m*v²

0.0084 = ½ * 0.0045 * v²

v² = 0.0084/0.00255 = 3.733

=> v = 1.93 m/s

4 0

3 years ago

Read 2 more answers

What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?

MA_775_DIABLO [31]

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

7 0

2 years ago

If a sealed syringe is plunged into cold water, in which direction will the syringe piston slide? *

Tamiku [17]

Answer:

Explanation:

can you help me with my question According to the narrator in Paragraph 3 of "The Celebrated Jumping Frog of Calaveras County," Simon Wheeler's tone throughout his entire tale was A earnest and sincere, B. excited and pressing, C. sad and melancholy,

5 0

2 years ago