How much displacement will a spring with a constant of 120N / m achieve if it is stretched by a force of 60N?
1 answer:
Answer:
Explanation:
There's a formula for this:
F being force, k being the spring constant, and displacement being the change in x
We are given the force and the spring constant, so this is essentially isolating the Δx term. Do 60N/120N per meter. The newtons cancel out and you get a final answer of Δx = 0.5 meters
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