Ask question

Ask question

All categories

Anuta_ua [19.1K]

2 years ago

8

Two identical rifles are shot at the same time, and the sound intensity level is 64.7 dB. What would be the sound intensity leve

l if only one rifle were shot

2 answers:

Ray Of Light [21]2 years ago

7 0

Answer:

61.7 dB

Explanation:

The sound intensity of Rifle can be calculated using this formula

I ( sound intensity ) = 10 * log ( I / IO) equation 1

where I = power/area

I = 64.7 dB

hence equation 1 becomes

64.7 = 10* log ( I / IO ) equation 2

note the sound intensity was produced by 2 identical rifle hence equation 2 will become

64.7 = 10 * log ( 2P / PO ) equation 3

for a single rifle (X) equation 3 becomes

= 64.7 - 10* log (2) = 64.7 - 10*0.30 = 64.7 - 3

= 61.7 dB

t

mixas84 [53]2 years ago

5 0

Answer:

The sound intensity is still the same. The sound intensity level does not depend on the number of sound sources but only the wave properties of the wave medium and the properties of the sound source. The wave properties of the medium includes the density and also the temperature.

Explanation:

You might be interested in

A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed

oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

$v=30j$

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

$u=475i$

c. The true velocity of the jet as a vector will be represented as w:

$w=u+v$

$w=475i+30j$

d. The true speed of the jet will be calculated as:

$IwI=\sqrt{(475)^2+(30)^2}$

$IwI=\sqrt{225625+900}$

$IwI=\sqrt{226525}$

$IwI=476 mi/h$

e. The direction of the jet will be:

$tita=tan^{-1}\frac{30}{475}$

$tita=tan^{-1}(0.0632)$

$tita=3.62degrees,or,N86.38degreesS$

7 0

2 years ago

Help asap please thank you

Tom [10]

Answer:

the answer its time

v = d/t

8 0

2 years ago

Read 2 more answers

According to ohm's law if you don't change the value of the resistor & you double the voltage in a circuit the amount of cur

Nana76 [90]

They double!! Hope im not too late!!

3 0

3 years ago

Help! Will Mark Brainliest!

boyakko [2]

Answer:

D 5m/s

Explanation:

6 0

3 years ago

An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is W/m². What is the rms

inn [45]

I think your question should be:

An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is

$S = 1.23*10^9 W/m^2$

What is the rms value of (a) the electric field and

(b) the magnetic field in the electromagnetic wave emitted by the laser

Answer:

a) $6.81*10^5 N/c$

b) $2.27*10^3 T$

Explanation:

To find the RMS value of the electric field, let's use the formula:

$E_r_m_s = sqrt*(S / CE_o)$

Where

$C = 3.00 * 10^-^8 m/s$ ;

$E_o = 8.85*10^-^1^2 C^2/N.m^2$ ;

$S = 1.23*10^9 W/m^2$

Therefore

$E_r_m_s = sqrt*{(1.239*10^9W/m^2) / [(3.00*10^8m/s)*(8.85*10^-^1^2C^2/N.m^2)]}$

$E_r_m_s= 6.81 *10^5N/c$

b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:

$B_r_m_s = E_r_m_s / C$ ;

$= 6.81*10^5 N/c / 3*10^8m/s$ ;

$B_r_m_s = 2.27*10^3 T$

8 0

3 years ago

Read 2 more answers