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Anuta_ua [19.1K]
3 years ago
8

Two identical rifles are shot at the same time, and the sound intensity level is 64.7 dB. What would be the sound intensity leve

l if only one rifle were shot
Physics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:

61.7 dB

Explanation:

The sound intensity of Rifle can be calculated using this formula

I ( sound intensity ) = 10 * log ( I / IO) equation 1

where I = power/area

I = 64.7 dB

hence equation 1 becomes

64.7 = 10* log ( I / IO ) equation 2

note the sound intensity was produced by 2 identical rifle hence equation 2 will become

64.7 = 10 * log ( 2P / PO ) equation 3

for a single rifle (X) equation 3 becomes

= 64.7 - 10* log (2) = 64.7 - 10*0.30 = 64.7 - 3

= 61.7 dB

t

mixas84 [53]3 years ago
5 0

Answer:

The sound intensity is still the same. The sound intensity level does not depend on the number of sound sources but only the wave properties of the wave medium and the properties of the sound source. The wave properties of the medium includes the density and also the temperature.

Explanation:

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Answer:

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Explanation:

<u>Given:</u>

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  • Number of turns of coil = N.
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(a):

The magnetic flux through the coil is given by

\phi = \vec B \cdot \vec A=BA\cos\theta

where,

\vec A = area vector of the coil directed along the normal to the plane of the coil.

\theta = angle between \vec B and \vec A.

Assuming, the direction of magnetic field is along the normal to the plane of the coil initially.

At any time t, the angle which magnetic field makes with the normal to the plane of the coil is 2\pi ft

Therefore, the magnetic flux linked with the coil at any time t is given by

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According to Faraday's law of electromagnetic induction, the emf induced in the coil is given by

e=-\dfrac{d\phi}{dt}\\=-\dfrac{d(NBA\cos(2\pi ft))}{dt}\\=-NBA(-2\pi f\sin(2\pi ft))\\=2\pi f NBA\sin(2\pi ft).

(b):

The amplitude of the alternating voltage is the maximum value of the emf and emf is maximum when \sin(2\pi ft)=1.

Therefore, the amplitude of the alternating voltage is given by

e_o = 2\pi ft NBA.

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Putting all these values,

e_o = 2\pi \times 33.33\times 100\times 0.1\times 10^{-2}=20.942\ Volts.

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So its displacement during exactly one time period is exactly zero.


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