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ycow [4]
3 years ago
11

What are some of the diseases that Natterson-Horowitz sees in both human and animal patients?

Mathematics
1 answer:
german3 years ago
3 0

Answer:

Some the disease that Natterson-Horowitz sees in both human and animal patients are congestive heart failure, brain tumors, leukemia, diabetes, arthritis and breast cancer.

Step-by-step explanation:

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5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
Plz help me here I really need it. Please and thanks!
Alik [6]

Answer:

no they are not proportional and the graph would be at points (1, 3) (5, 9)

Step-by-step explanation:

Can i have brainliest Please?

8 0
2 years ago
Expand completely using the Binomial Theorem<br> (3y - x)^4
AleksAgata [21]

Answer:

In standard form it is x^4 - 12x^3y + 54x^2y^2 - 108x y^3 + 81y^4.

Step-by-step explanation:

(3y)^4 + 4C1(3y)^3(-x) + 4C2(3y)^2(-x)^2 + 4C3(3y)(-x)^3  + (-x)^4

= 81y^4 - 108y^3x + 54y^2x^2 - 12yx^3 + x^4

4 0
2 years ago
23=x-9;x=14 how do I figure out if this is a solution of the equation?
serious [3.7K]
There is no solution because x is incorrect.

x should be 32
4 0
3 years ago
Read 2 more answers
Marisa has at most $50 to spend on clothes. She wants to buy jeans that cost $25. With the money that she has left over, she wan
Reika [66]

50 \geqslant 6x + 25

6 0
2 years ago
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