<span>To relate or measure the by the quantity of something, not against the quantity</span>
Answer:
The family may be addicted to technology by using their cellphones to communicate is still communicating in a way, but it would be better to use social face- to - face interactions.
Explanation:
<u>Option b. </u>A smaller magnitude of momentum and more kinetic energy.
<h3>What is a momentum?</h3>
- In Newtonian physics, an object's linear momentum, translational momentum, or simply momentum is defined as the product of its mass and velocity.
- It has both a magnitude and a direction, making it a vector quantity. The object's momentum, p, is defined as: p=mv if m is the object's mass and v is its velocity (also a vector quantity).
- The kilogram metre per second (kg m/s), or newton-second in the International System of Units (SI), is the unit used to measure momentum.
- The rate of change of a body's momentum is equal to the net force exerted on it, according to Newton's second law of motion.
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OPTION C The car is accelerating because the direction of velocity is changing explains why a race car going around a curve is accelerating, even if the speed is constant
- When a body is in uniform circular motion ( constant speed ), it will continuously cheanges its direction and so the body is accelerating
- The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating.
- As a vector quantity, acceleration has a direction attached to it. The acceleration vector's direction is determined by two factors: if the thing is slowing down or speeding up the direction the thing is travelling in (+ or -)
- The following general rule is used to calculate acceleration:
An object's acceleration will be in the opposite direction of its velocity if it is slowing down.
You may use this basic concept to determine if an object's acceleration is positive or negative, to the right or left, up or down, etc.
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(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².
(b) The work done, in stretching the spring from x1 to x2 is 11.25 J.
(c) The work, necessary to stretch the spring from x = 0 to x3 is 64.28 J.
<h3>
Work done in the spring</h3>
The work done in stretching the spring is calculated as follows;
W = ¹/₂kx²
W(1 to 2) = ¹/₂K₂Δx²
W(1 to 2) = ¹/₂(250)(0.65 - 0.35)²
W(1 to 2) = 11.25 J
W(0 to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃
W(0 to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)
W(0 to 3) = 64.28 J
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