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allochka39001 [22]
3 years ago
15

What is the molality of a solution containing 100 grams of glucose (C6H12O6, molar mass = 180 g/mol) dissolved in 2.5 kg of wate

r?
Group of answer choices

40 m

0.22 m

72 m

7200 m
Chemistry
1 answer:
meriva3 years ago
6 0

Answer:

The answer to your question is molality = 0.22

Explanation:

Data

molality = ?

mass of glucose = 100 g

molar mass of glucose = 180 g

mass of water = 2.5 kg

Process

1.- Calculate the moles of glucose using proportions

                180 g ------------------ 1 mol

                100 g ------------------  x

                   x = (100 x 1) / 180

                   x = 100 / 180

                   x = 0.56 moles

2.- Calculate the molality

Formula

molality = moles / mass of solvent

- Substitution

molality = 0.56 / 2.5

- Simplification

molality = 0.22

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0.350 mol of a solid was dissolved in 260 mL of water at 21.2 oC. After the solid had fully dissolved, the final temperature of
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                                       = 26.5 - 21.2

                                        = 5.3 °C

H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J

Molar heat = \frac{5765J}{0.350mol}

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Answer:

The answer to your question is given below.

Explanation:

Rate is simply defined as quantity per unit time. Mathematically it is represented as:

Rate = Quantity /time

Thus, we can obtain the rate as follow:

1. Quantity = 20 sandwich

Time = 10 mins

Rate =?

Rate = Quantity /time

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Time = 10 mins

Rate =?

Rate = Quantity /time

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3. Quantity = 40 sandwich

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4. Quantity = 50 sandwich

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Thus, the complete table is given as follow:

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20 >>>>>>> 10 min >>>>>>>>>> 2

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