What is the molality of a solution containing 100 grams of glucose (C6H12O6, molar mass = 180 g/mol) dissolved in 2.5 kg of wate
r?
Group of answer choices
40 m
0.22 m
72 m
7200 m
1 answer:
Answer:
The answer to your question is molality = 0.22
Explanation:
Data
molality = ?
mass of glucose = 100 g
molar mass of glucose = 180 g
mass of water = 2.5 kg
Process
1.- Calculate the moles of glucose using proportions
180 g ------------------ 1 mol
100 g ------------------ x
x = (100 x 1) / 180
x = 100 / 180
x = 0.56 moles
2.- Calculate the molality
Formula
molality = moles / mass of solvent
- Substitution
molality = 0.56 / 2.5
- Simplification
molality = 0.22
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Answer:
d = 0.93 g/cm³
Explanation:
Given data:
Mass of object = 28 g
Volume of object = 3cm×2cm×5cm
density of object = ?
Solution:
Volume of object = 3cm × 2cm ×5cm
Volume of object = 30 cm³
Density of object:
d = m/v
by putting values,
d = 28 g/ 30 cm³
d = 0.93 g/cm³
Answer:
6.02×10^23 atoms
Explanation:
Avogadros constant is a number that states the amount of atoms in one mole of a substance which is 6.02×10^23 to 3 significant figures.
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