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faust18 [17]
3 years ago
9

If a resource is nonrenewable, it

Chemistry
1 answer:
Goshia [24]3 years ago
7 0

Answer:

Can't be used again

Explanation:

...................................

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A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us
Zinaida [17]

Answer:

A. 96.3 mg/dL

Absolute error: 5.7 mg/dL

Relative error: 5.6%

B. 97.2 mg/dL

Absolute error: 4.8 mg/dL

Relative error: 4.7%

C. 104.8 mg/dL

Absolute error: 2.8 mg/dL

Relative error: 2.7%

D. 111.5 mg/dL

Absolute error: 9.5 mg/dL

Relative error: 9.3%

E. 110.5 mg/dL

Absolute error: 8.5 mg/dL

Relative error: 8.3%

Explanation:

The formula for the absolute error is:

Absolute error = |Actual Value - Measured Value|

The formula for the relative error is:

Relative error = |Absolute error/Actual value|

In your exercise, we have that

Actual Value = 102.0 mg/dL

A. 96.3 mg/dL:

E_{ABS} = |102.0 - 96.3| = 5.7mg/dL

E_{R} = \frac{5.7}{102} = 0.056 = 5.6%

B. 97.2 mg/dL

E_{ABS} = |102.0 - 97.2| = 4.8mg/dL

E_{R} = \frac{4.8}{102} = 0.047 = 4.7%

C. 104.8 mg/dL

E_{ABS} = |102.0 - 104.8| = 2.8mg/dL

E_{R} = \frac{2.8}{102} = 0.027 = 2.7%

D. 111.5 mg/dL

E_{ABS} = |102.0 - 111.5| = 9.5mg/dL

E_{R} = \frac{9.5}{102} = 0.093 = 9.3%

E. 110.5 mg/dL

E_{ABS} = |102.0 - 111.5| = 8.5mg/dL

E_{R} = \frac{8.5}{102} = 0.083 = 8.3%

4 0
3 years ago
If the reactants on the left side of a chemical equation are C3H8 + 5O2, the products in a balanced equation could be
Basile [38]
Holy I'm not that smart lol but I'll get back to you
6 0
3 years ago
Read 2 more answers
Compared to the particles in a gas, the particles in a solid move
pentagon [3]
B. Slower than the gas is the answer
3 0
3 years ago
To determine the freezing point depression of a LiCl solution, Toni adds 0.411 g of LiCl to the sample test tube along with 19.7
Cerrena [4.2K]

Answer:

LiCl = 0.492 m

Explanation:

Molal concentration is the one that indicates the moles of solute that are contained in 1kg of solvent.

Our solute is lithium chloride, LiCl.

Our solvent is distilled water.

We do not have the mass of water, but we know the volume, so we should apply density to determine mass.

Density = mass / volume

Density . volume = mass

1 g/mL . 19.7 mL = 19.7 g

We convert g to kg → 19.7 g . 1 kg / 1000g = 0.0197 kg

Let's determine the moles of LiCl

0.411 g . 1 mol / 42.394 g = 9.69×10⁻³ moles

Molal concentration (m) = 9.69×10⁻³ mol / 0.0197 kg → 0.492 m

7 0
2 years ago
How many moles are in 123.0g (NH4)2SO4
Luda [366]
Here you go! There are 0.9307 moles in 123.0 g of the compound. I solved this by using a fence post method. I calculated the number of grams in one mol of (NH4)2 SO4 and got 132.16.

I did this by finding the atomic mass of each element on the periodic table (my work is in the color blue for this step)

After that, i divided the given mass by the mass of one mol of the compound.

The answer is 0.9307 moles!! I hope this helped you! :))

7 0
2 years ago
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