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4 years ago

If a resource is nonrenewable, it

Chemistry

1 answer:

Goshia [24]4 years ago

7 0

Answer:

Can't be used again

Explanation:

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How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Show all of the work needed to solve this

vovikov84 [41]

V=4.8 L
c=5.0 mol/L
M(Mg)=24.3 g/mol

1) n(HCl)=cv

2) m(Mg)=M(Mg)n(HCl)/2

3) m(Mg)=M(Mg)cv/2
m(Mg)=24.3*5*4.8/2=291.6 g

7 0

3 years ago

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Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring

ludmilkaskok [199]

Answer:

1.20 V

Explanation:

$Pb(s) + Br_2(l)\rightarrow Pb^{2+}(aq) + 2Br^-(aq)$

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

Given,

$Pb^{2+}(aq) + 2 e^-\rightarrow Pb(s)$

$E^0_{[Pb^{2+}/Pb]}= -0.13\ V$

$Br_2(l) + 2 e^-\rightarrow 2 Br(aq)$

$E^0_{[Br_2/Br^{-}]}=+1.07\ V$

$E^0=E^0_{[Br_2/Br^{-}]}- E^0_{[Pb^{2+}/Pb]}$

$E^0=+1.07- (-0.13)\ V=1.20\ V$

6 0

4 years ago

How did the concentration of iodide ions change in these two trials, how did the rate change accordingly?

AfilCa [17]

The concentration of iodide ions doubled.
From what was found in part a, the reaction rate increases by a factor of about 4.

3 0

4 years ago

Single-celled organisms need a microscope to be seen... O True O False

NNADVOKAT [17]

Answer:

True

Explanation:

Microscope is an instrument which is used to observe small objects. There are many types of microscope with a different magnitude.

4 0

3 years ago

Calculate the molarity of 0.50 mol MgCl2 in 750 ml of solution.

Vedmedyk [2.9K]

Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.

Molarity :

It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .

It uses unit M or $\frac{mol}{L}$

It can be formulated as :

$Molarity (\frac{mol}{L} ) = \frac{mole of solute (mol)}{volume of solution (L)}$

Given : mol of MgCl₂ (solute ) = 0.50 mol

Volume of solution = 750 mL

Following steps can be done :

Step 1 ) To convert volume of solution from mL to L

1 L = 1000 mL

$Volume of solution = 750 mL * \frac{1 L}{1000mL}$

Volume of solution = 0.750 L

Step 2) To find molarity

Plugging mole of solute and volume of solution in molarity formula as :

$Molarity = \frac{0.50 mol}{0.750 L }$

$Molarity = 0.67 \frac{mol}{L}$

Hence molarity of MgCl₂ solution is 0.67 M

4 0

4 years ago

Read 2 more answers