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Sholpan [36]
3 years ago
11

A car travelling at 14.0 m/s approaches a traffic light. The driver applies the brakes and is able to come to halt in 5.6 s. Det

ermine the average acceleration of the car during this time interval.
Physics
1 answer:
FromTheMoon [43]3 years ago
3 0

Answer:

a=2.5\ m/s^2

Explanation:

Given that,

Initial speed of the car, u = 14 m/s

Finally, it comes to rest, v = 0

Time, t = 5.6 s

We need to find the average acceleration of the car during this time interval. We know that,

a=\dfrac{v-u}{t}\\\\a=\dfrac{0-14}{5.6}\\\\a=-2.5\ m/s^2

So, the acceleration of the car is 2.5\ m/s^2 in the opposite direction of motion.

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2 because when you are doing this it causes friction Which then cause the balloon to stick
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During normal beating, the heart creates a maximum 4.00-mV potential across 0.300 m of a person’s chest, creating a 1.00-Hz elec
erik [133]

Answer:

(a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

Explanation:

Given that,

Maximum potential = 4.00 mV

Distance = 0.300\ m

Frequency = 1.00 Hz

(a). We need to calculate the maximum electric field strength

Using formula of the potential difference

\Delta V=Ed

E=\dfrac{\Delta V}{d}

E=\dfrac{4.00\times10^{-3}}{0.300}

E=0.0133\ V/m

(b). We need to calculate the maximum magnetic field strength in the electromagnetic wave

Using formula of the maximum magnetic field strength in the electromagnetic wave

B=\dfrac{E}{c}

Put the value into the formula

B=\dfrac{0.0133}{3\times10^{8}}

B=4.433\times10^{-11}\ T

(c). We need to calculate the wavelength of the electromagnetic wave

Using formula of wavelength

c=f\lambda

\lambda=\dfrac{c}{f}

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{1.00}

\lambda=3\times10^{8}\ m

Hence, (a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

4 0
3 years ago
A force of 50 N stretches a string by 4 cm,calculate the elastic constant.
murzikaleks [220]

Answer:

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A non-relativistic particle of mass m moves in one dimension x under the force
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Answer:

U = - (x⁴ / 4 - b x² / 2) , c) The function is zero  for x = 0 and √2

Explanation:

a and b) Strength and potential energy are related

               F = - dU / dx

Therefore to find the energy we must integrate

            ∫ dU = -∫ F dx

            ∫ dU = - ∫ (a x³ –b x) dx

Let's make the integration

             U = - (x⁴ / 4 - b x² / 2)

We evaluate the integral between the value

            U - U₀ = -x⁴ / 4 + x² / 2 - (-x₀⁴ / 4 + x₀² / 2)

The arbitrary constant is zero, so that U is zero in the zero position

                U₀ = 0 for x₀ = 0

c) Mechanical energy is the sum of kinetic energy plus potential energy

        Em = K + U

        Em = ½ m v² + ½ (x² -x⁴ / 2)

       E = ½ m v² + ½ x² (1 - x² / 2)

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        2 (E –K) = x² (1-x² / 2)

At the return points K = 0

The zero points of this function are

     x = 0

     (1- x² / 2) = 0

     x² = 2

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The function is zero

       x = 0 and √2

d) the movement is bounded for energy values ​​less than or equal to

            E <= ½ x² (1-x² / 2)

e) for this part we resolved Newton's second law

            F = m a

            ax³ - b x = m d²x / dt²

            d²x / dt² = -b / m x + a / m x³3

The linear term gives a simple harmonic movement

             w₀² = b / m

             d²x / dt² = - w₀² x + a / m x³

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