Since it was stated that it must move at constant
velocity, so the only force it must overpower is the frictional force.
So the equation is:
F cos θ = Ff
F cos 36 = 65 N
F = 80.34 N
<span>So the nurse must exert 80.34 N of force</span>
Explanation:
A wavefront is the long edge that moves, for example, the crest or the trough. Each point on the wavefront emits a semicircular wave that moves at the propagation speed v. These are drawn at a time t later, so that they have moved a distance s = vt.
Answer:
No. of moles, n = 25.022 moles
Given:
Volume of gas in tank, V = 29.1 l
Temperate of gas, T = 
= 273 + 35.8 = 308.8 K
Pressure of gas, P = 21.8 atm
Solution:
Making use of the ideal gas equation which given as:
PV = nRT
where
R = Rydberg's constant = 0.0821 L-atm/mol-K
Re-arranging the above formula for 'n' and putting the values in the above formula:
n = 25.022
Answer:
Explanation:
Make up a question.
The only change is going to be c.
Suppose they aluminum starts our higher at 50oC
Suppose the copper starts out at 20oC
Suppose the mass of both are 25 grams.
Aluminum
m*2c * deltat
- deltat = 50 - x
- c = 2*c
- m = 25
Copper
m*c*deltat
deltat = x - 20
m = 25
c = c
Now since the amount of heat is the same (this starts out on a heated slab of something).
m*2c * (50 - x) = m * c * x - 20 The m and the c are the same. Cancel them out.
2 * (50 - x) = (x - 20) Remove the brackets.
100 - 2x = x - 20 Add 20 to both sides.
120 - 2x = x Add 2x to both sides.
120 = 3x Divide by 3
x = 40
What does this tell you?
It tells you that the temperature of the aluminum is only going to drop 10 degrees
The copper is going to gain 40 - 20 = 20 degrees.
The heat transfer is actually the same. It doesn't take as much heat to heat copper as it does aluminum. That's shown by the difference in how the temperature changes. One looses 10 degrees. The other gains 20. The transfer is the same because of the way the "c" operates.
