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umka2103 [35]
3 years ago
14

A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. Assume

that any other unbalanced forces are negligible. What is the speed of the wreckage just after the collision?
Physics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

<em>12.23m/s</em>

Explanation:

<em>Let's recall that</em>

<em />

<em>The Initial momentum in (East)axis  = 900 x 15 which is = 13500 N-s </em>

<em> </em>

<em>Initial momentum in (North) axis = 750 x 20 which is = 15000 N-s </em>

<em />

<em>Total initial momentum  becomes = √[(13500)^2 + (15000)^2] = 20180.44 N-s </em>

<em> The  initial momentum direction is  at θ* East of North </em>

<em />

<em> Therefore, tanθ = 13500/15000 = 0.9 = tan42* </em>

<em>  tanθ=42</em>

<em> </em>

<em>The speed of the wreckage after collection is,</em>

<em />

<em>Recall that The law of momentum conservation states that </em>

<em>Momentum initial = Momentum final </em>

<em> </em>

<em>20180.44 = (900+750) x v </em>

<em> </em>

<em>v = 12.23 m/s</em>

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Answer:

8.333*10^-6 ohms

Explanation:

Resistivity of a material is expressed as;

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Given

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A = 0.5mm^2

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Substitute into the formula;

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p = 0.0000025/0.3

p = 8.333*10^-6

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Answer:

Option A

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Explanation:

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