Answer:
We are in Tropical Rainforests.
Explanation:
Biome is basically an ecological region of earth that has specific type of flora and fauna (plants and animals). Every biome has specific abiotic factors like specific climate, temperature, geology, vegetation, soils and relief.
There are total 8 biomes in the world
- Desert
- Grassland
- Temperate Boreal Forest
- Chaparral
- Tropical Savanna
- Tropical Rainforest
- Tundra
- Temperate Deciduous Forest
Now in our question, we have been given some conditions and are asked to identify the biome. The annual precipitation is about 300 cm and the average temperature is around 25 degrees Celsius.
Now, if we study the characteristics of all these biomes, it is very simple to identify that the biome is Tropical Rainforest.
Important characteristics of Tropical Rainforest:
- They receive more than 200 cm of rain each year.
- The temperature of the biome is between 20 degree Celsius and 25 degree Celsius during the whole year.
- Around 50 percent of the animal specie of the world are found here.
<em>Note: </em><em>You can study the characteristics of world’s other biomes in the link :
http://www.physicalgeography.net/fundamentals/9k.html
</em>
Hope it helps! :)
Answer:
1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵
Explanation:
1) Ca:
Its atomic number is 20. So it has 20 protons and 20 electrons.
Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.
So, you have two more electrons (20 - 18 = 2) to distribute.
Those two electrons go the the orbital 4s.
Finally, the electron configuration is [Ar] 4s².
2) Pm
The atomic number of Pm is 61, so it has 61 protons and 61 electrons.
Pm is in the row (period) 6. So, the noble gas before Pm is Xe.
The atomic number of Xe is 54.
Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.
The resultant distribution for Pm is: [Xe]6s² 4f⁵.
The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
Answer:6 atoms
Explanation:Each NaOH has one Na and one O and one H. Therefore, 2 NaOH has 6 atoms.
Answer:
Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception
