Answer:
9 cm²
Step-by-step explanation:
Two wires are attached 6 feet up a tree and 3 feet from the base of the tree. About how much TOTAL wire was used?
We solve the above question, using the Area of a Triangle
Area = 1/2 × Base × Height
Area = 1/2 × 3 × 6
Area = 9 cm²
Therefore, the total wore that was used was 9cm² of wire
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
Answer:
There are five triangles in a heptagon. A heptagon is a seven-sided polygon.
Step-by-step explanation:
Answer/Step-by-step explanation:
✔️Slope of the first graph:
Using two points on the line, (0, 1) and (3, 2),

Slope = ⅓
✔️Slope of the second graph:
Using two points on the line, (0, 0) and (1, 1),

Slope = 1
✔️Slope of the third graph:
Using two points on the line, (0, 1) and (2, 2),

Slope = ½

Let's solve ~




Hence, the correct choice is D