Question

Write the chemical symbols for three different atoms or atomic anions with 36 electrons

Answer 1

If you look at the periodic table, Krypton has an atomic number of 36. Krypton is one of the noble gases. They are a group of elements that are very stable because they obey the Octet Rule. As a result, other elements try to conform the electronic configurations of the nearest noble gases to them. They either give or take electrons in their valence shell.

The three atoms that have 36 electrons are: Kr (Krypton), Br⁻ (Bromide), and Rb⁺(Rubidium ion).

Answer 2

Explanation:

An element with atomic number 36 is krypton and symbol which represents it is Kr.

Atomic number of bromine is 35 and when it gains an electron it forms bromine ion ($Br^{-}$). Total number of electrons in $Br^{-}$ are 36.

Atomic number of Selenium is 34. When it gains two electrons then it forms $Se^{2-}$ ion. Therefore, total number of electrons present in $Se^{2-}$ ion are 36.

Hence, chemical symbols for three different atoms or atomic anions with 36 electrons are Kr, $Br^{-}$, and $Se^{2-}$.