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Citrus2011 [14]
3 years ago
13

If 5 L of butane is reacted what volume of carbon dioxide is produced ILL GIVE BRAINLIEST

Chemistry
1 answer:
Len [333]3 years ago
8 0

Answer: First, here is the balanced reaction:  2C4H10  +  13O2  ===>  8CO2  +  10H2O.

This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.

Next, let's determine how many moles of butane are burned.  This is obtained by

5.50 g / 58.1 g/mole  =  0.0947 moles butane.  As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947  =  0.1894 moles CO2.

Now we need to figure out the volume.  This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions:  273 K and 1 atmosphere.

We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).

V = 0.1894 x 0.082 x 273.0 / 1  =  4.24 Liters.

Explanation:

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The temperature at which a liquid becomes a solid is the:
Olenka [21]
The answer is "c" because solidification or freezing is the term used for the process in which a liquid becomes a solid.<span> Freezing is an exothermic process that also is an example of a phase transition</span>
3 0
3 years ago
Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of
dsp73
The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.

Molarity is mol HNO3 / L of solution. This is our aim

The given percentage is 0.68 g HNO3/ g solution

multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain

0.016 mol/ mL or 16.23 mol/ L (M)

6 0
3 years ago
The following initial rate data are for the reaction of hypochlorite ion with iodide ion in 1M aqueous hydroxide solution: OCI+r
Vinil7 [7]

Answer:

Rate = k [OCl] [I]

Explanation:

OCI+r → or +CI

Experiment [OCI] M I(-M) Rate (M/s)2

1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3

2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3

3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3

4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3

The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.

In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.

In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.

The rate law is given as;

Rate = k [OCl] [I]

5 0
3 years ago
What would be the best product to neutralize battery acid
Anna [14]

Answer:

Baking Soda a base

Explanation:

We know that to neutralize an acid we add base to it. Baking Soda is a type of base so when we add Baking Soda or any other base to battery acid or any other acid we can neutralize it and get salt and water.

Acids are the substance which are sour in taste and can turn blue litmus paper red. For example, Lemon and Orange.

Bases are the substance which are bitter in taste and can turn red litmus paper blue. For example, Baking Soda and Soap.

7 0
3 years ago
Read the following chemical equation: Ti + 2Cl2 → TiCl4 Which statement best identifies and describes the reducing agent in the
goldenfox [79]

Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.

Explanation:

  • Firstly, we need to identify the reducing agent and the oxidizing agent.
  • The reducing agent: is the agent that has been oxidized via losing electrons.
  • The oxidizing agent: is the agent that has been reduced via gaining electrons.
  • Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂  gains one electron  and its oxidation state is changed from 0 to -1.
  • So, Ti is the reducing agent because its oxidation state changes from  0 to +4.
  • Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
  • Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
4 0
3 years ago
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