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3 years ago

How much heat (Btu) is prod uced by a 150-W light bulb that is on for 20-hours?

Engineering

1 answer:

erica [24]3 years ago

8 0

Answer:

heat produced by 150 watt bulb is 510 Btu

Explanation:

Given data:

Power of bulb is 150 W

Duration for light is 20 hr

We know that 1 Watt = 3.4 Btu

hence using above conversion value we can calculate the power in Btu unit

so for $150 W\ bulb = 150\times 3.4 = 510 Btu$

therefore, 150 W bulb consist of 510 Btu power for 20 hr

output heat by 150 watt bulb is 510 Btu

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The sports car has a weight of 4900 lblb and center of gravity at GG. If it starts from rest it causes the rear wheels to slip a

Zinaida [17]

Answer:

2.27secs

Explanation:

The car will take 2.27secs to reach a speed of 10 ft/s.

Kindly go through the attached files for a step by step solution that will show you how the answer was gotten and the normal reaction of both the front and rear wheels.

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3 years ago

A Carnot engine has a piston displacement volume of 7.5 liters. The volume at the beginning of heat addition is 1.0 liters, the

RideAnS [48]

Answer:

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Explanation:

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3 years ago

A pump is used to transport water from a reservoir at one elevation to another reservoir at a higher elevation. If the elevation

erastova [34]

Answer:b

Explanation:

We know power delivered by Pump is

$P=\rho \times Q\times g\times \Delta H$

where $P\rho$ =Density of fluid

$Q$ =Flow rate

$g$ =acceleration due to gravity

$\Delta H$ =Change in Elevation

If $\Delta H$ is increased by 4 time then

$P'=\rho \times Q\times g\times (4\Delta H)$

$P'=4 P$

So power increases by four times.

4 0

3 years ago

A plant has ten machines and currently operates two 8-hr shift per day, 5 days per week, 50 weeks per year. the ten machines pro

Zarrin [17]

Answer:

83.6%

Explanation:

On its current schedule, the plant can theoretically produce ...

(30 pc/h/machine)(10 machine)(8 h/shift)(2 shift/day)(5 day/wk)(50 wk/yr)

= (30)(10)(8)(2)(5)(50) pc/yr = 1,200,000 pc/yr

On the proposed schedule, this production becomes ...

(30 pc/mach)(10 mach)(8 h/sh)(3 sh/da)(6 da/wk)(51 wk/yr)

= (30)(10)(8)(3)(6)(51) pc/yr = 2,203,200 pc/yr

The increase in capacity is ...

(2,203,200/1,200,000 -1) × 100% = 83.6% . . . capacity increase

_____

<em>Additional comment</em>

The number of parts per shift did not change. Only the number of shifts per year changed. It went up by a factor of (3/2)(6/5)(51/50) = 1.836. Hence the 83.6% increase in capacity.

We have to assume that maintenance and repair are done as effectvely as before in the reduced down time that each machine has.

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2 years ago

1. A turbine in a steam power plant operates isentropically with an inlet pressure (P3) of 3.5 MPa and inlet temperature (T3) of

sergey [27]

Answer:

See attached picture.

Explanation:

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3 years ago