Answer:
porosity = 0.07 or 7%
dry bulk density = 3.25g/cm3]
water content =
Explanation:
bulk density = dry Mass / volume of sample
dry mass = 0.490kg = 490g
volume = πr2h = 3.142 * 2 *2 *12 = 150.8cm3
density = 490/150.8 = 3.25g/cm3
porosity =
=
= 0.07 or 7%
water content =
= 7%
Answer:
Explanation:
Considering the relation of the equilibrium vacancy concentration ;
nv/N = exp (-ΔHv/KT)
Where T is the temperature at which the vacancy sites are formed
K = Boltzmaan constant
ΔHv = enthalpy of vacancy formation
Rearranging the equation and expressing in term of the temperature and plugging the values given to get the temperature. The detailed steps is as shown in the attached file
Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
<h3>How does a mass
airflow sensor work?</h3>
An MAF is one that consist of two sensing wires. One is known to be heated by the use of electrical current, while the other is not.
There are different kinds of wires for different kinds of purposes.
Tech A saying that mass airflow sensors determine mass airflow based on engine speed and manifold pressure is incorrect because that is not the role of the mass airflow sensors.
l
As air flows across the heated wire, it cools down. Hence, Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
Learn more about airflow sensor from
brainly.com/question/15188617
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Answer:
L = Henry
C = Farad
Explanation:
The electrical parameter represented as L is the inductance whose unit is Henry(H).
The electrical parameter represented as C is the inductance whose unit is Farad
Resonance frequency occurs when the applied period force is equal to the natural frequency of the system upon which the force acts :
To obtain :
At resonance, Inductive reactance = capacitive reactance
Equate the inductive and capacitive reactance
Inductive reactance(Xl) = 2πFL
Capacitive Reactance(Xc) = 1/2πFC
Inductive reactance(Xl) = Capacitive Reactance(Xc)
2πFL = 1/2πFC
Multiplying both sides by F
F * 2πFL = F * 1/2πFC
2πF²L = 1/2πC
Isolating F²
F² = 1/2πC2πL
F² = 1/4π²LC
Take the square root of both sides to make F the subject
F = √1 / √4π²LC
F = 1 /2π√LC
Hence, the proof.