Answer:
The final equilibrium T_{f} = 25.7[°C]
Explanation:
In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.
That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.
The temperature of thermal equilibrium will be T_f.
The heat absorbed by water will be equal to the heat rejected by Iron.
Heat transfer can be found by means of the following equation.
where:
Qiron = Iron heat transfer [kJ]
m = iron mass = 200 [g] = 0.2 [kg]
T_i = Initial temperature of the iron = 300 [°C]
T_f = final temperature [°C]
Cp_iron = 437 [J/kg*°C]
Cp_water = 4200 [J/kg*°C]
![0.2*437*(300-T_{f})=1*4200*(T_{f}-20)\\26220-87.4*T_{f}=4200*T_{f}-84000\\26220+84000=4200*T_{f}+87.4*T_{f}\\110220 = 4287.4*T_{f}\\T_{f}=25.7[C]](https://tex.z-dn.net/?f=0.2%2A437%2A%28300-T_%7Bf%7D%29%3D1%2A4200%2A%28T_%7Bf%7D-20%29%5C%5C26220-87.4%2AT_%7Bf%7D%3D4200%2AT_%7Bf%7D-84000%5C%5C26220%2B84000%3D4200%2AT_%7Bf%7D%2B87.4%2AT_%7Bf%7D%5C%5C110220%20%3D%204287.4%2AT_%7Bf%7D%5C%5CT_%7Bf%7D%3D25.7%5BC%5D)
It is important if you are a salesperson that you see a pattern of what people want so you you can sell what you think will be te new fad.
Assuming the lines need to be straight, I'd go with a triangle (the lines can keep going to infinity too, that's fine). But that only has 3 intersections of 2 lines, if you need all 3 lines to intersect exactly 3 times and need to be straight, it can't be done, I don't think. However, you could lay each line on top of each other to have infinite intersection points, but that's probably not what they want.
Answer:(0,2)
Explanation:
Take origin (0,0) as point A and when you move one block east to point B then coordinates becomes (1,0)
Now you move 4 blocks north to point C then the coordinates of point C becomes (4,1)
Similarly, You move 1 block west to point D such that its co-ordinates becomes (0,4)
Finally you move from D to E, 2 blocks south such that point E becomes (0,2)
So, E is the friend's house and its coordinates are (0,2)
It can be diagramatically be represented by figure given below
Answer: Magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.
Explanation:
Given: Density = 80 
(1 n = 
m) = 
= 1.0 mm (1 mm = 0.001 m) = 0.001 m
= 3.0 mm = 0.003 m
r = 2.0 mm = 0.002 m (from the symmetry axis)
The charge per unit length of the cylinder is calculated as follows.
Substitute the values into above formula as follows.
![\lambda = \rho \pi (r^{2}_{2} - r^{2}_{1})\\= 80 \times 10^{-9} \times 3.14 \times [(0.003)^{2} - (0.001)^{2}]\\= 2.01 \times 10^{-12} C/m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Crho%20%5Cpi%20%28r%5E%7B2%7D_%7B2%7D%20-%20r%5E%7B2%7D_%7B1%7D%29%5C%5C%3D%2080%20%5Ctimes%2010%5E%7B-9%7D%20%5Ctimes%203.14%20%5Ctimes%20%5B%280.003%29%5E%7B2%7D%20-%20%280.001%29%5E%7B2%7D%5D%5C%5C%3D%202.01%20%5Ctimes%2010%5E%7B-12%7D%20C%2Fm)
Therefore, electric field at r = 0.002 m from the symmetry axis is calculated as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.
