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attashe74 [19]
2 years ago
14

What is the lowest possible temperature

Physics
2 answers:
iris [78.8K]2 years ago
8 0
<span>physically impossible-to-reach temperature of zero kelvin, or minus 459.67 degrees Fahrenheit (minus 273.15 degrees Celsius), atoms would stop moving. </span>
HACTEHA [7]2 years ago
6 0
The lowest possible temperature is absolute zero. However scientists have not reached this temperature, rather they have come very close to absolute zero.

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The density of water is 1000kg/m3 and the density of ice is 900kg/m3. When 0.050 m3 of water is frozen, what will be the new vol
Bingel [31]
Sorry if this answer is a bit late...

We know that the volume of the water is 0.5 cube meters.

The density of water is 1.000 g/m^3 (that's the real density of water... maybe typos?)

The density of ice is 0.900 g/m^3 (that's the approximate density of ice)

First, let's multiply the volume of water by the density of the water to get the mass, since we know that the mass does not change with the ice gets frozen.

0.5 * 1.000 = 0.500 g

Now, let's divide that by the density of ice to get the volume of the ice.

0.500 / 0.900 = 5/9 cube meters

≈ 0.556 cube meters.

The volume of the ice is 5/9 or 0.556 cube meters.

Have an awesome day! :)
4 0
2 years ago
What is the mass number of an atom with 5 protons and 7 neutrons?
sergij07 [2.7K]
Boron I think look at the periodic table
8 0
3 years ago
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A decaliters how many times larger than 1 million
Mama L [17]
The answer is 100 times


8 0
2 years ago
A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav
gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2        (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

v^2=v_o^2+2gy

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}

With this value you can find the spring constant k from the equation (1):

mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

W=F_e\\\\mg=kx

you solve the last expression for x:

x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}

Next, you calculate x from the equation (1):

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m

The net fire is stretched 2.72 m

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2 years ago
Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table.
emmainna [20.7K]
C. It doubles I hope this helps and good luck
6 0
3 years ago
Read 2 more answers
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