1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Readme [11.4K]
4 years ago
10

The maximum mass the can be hung vertically from a string without breaking the string is 10kg. A length of this string that is 2

m long is used to rotate a 0.5kg object in a circle on a frictionless table with the string horizontal. The maximum speed that the mass can attain under these conditions without the string breaking is most nearly:
Answer is 20 m/s
Please show me how I can get the answer. Thank you.
Physics
1 answer:
vichka [17]4 years ago
0 0

Answer:

Explanation:

Think about circular motion when answering this question. First determine the maximum force that can be applied on the string. F = mg so F = (10)(10) = 100 N. Then determine the centripetal acceleration of the .5 kg mass, a = F/m so a = 100/.5 = 200 m/s².  On the equation sheet, use equation a(centripetal acceleration) = v²/r so 200 = v²/2 therefore v = 20 m/s. Hope this helps!

You might be interested in
Fig 3.1 shows the speed-time graph of a firework rocket as it rises and then falls to the ground
Minchanka [31]

The acceleration of an object in free fall motion is the constant acceleration due to gravity

(i) The gradient of the rocket at point <em>B</em> is approximately<u> -9.81 m/s²</u>

<u />

(ii) The reason why the gradient is -9.81 m/s² is as follows;

The given graph is the speed to time graph with the upward direction taken as positive

  • Gradient of the speed to time graph is the acceleration

Given that at point B the object is at the maximum point, the upward motion due to the rocket stops, the motion of the rocket is then due to gravity

Therefore, the gradient at <em>B</em>, is given as follows;

Gradient = \dfrac{\Delta v}{\Delta t } = \dfrac{d(u + a \cdot t)}{dt} =a

  • Force = Mass × Acceleration

At point <em>B</em> the only force acting on the rocket is the force of gravity, therefore, the acceleration of the rocket at <em>B</em>, a = g, acceleration due to gravity ≈  9.81 m/s², and the rocket is falling due to its weight

  • Force acting at B = Weight = Mass × Acceleration due to gravity, g

Therefore, only gravitational force is acting on the rocket when the direction of the rocket changes and rocket falls freely, at <em>B</em>, and the acceleration of the rocket at <em>B</em> = g = 9.81 m/s²

Learn more about free fall motion here:

brainly.com/question/16808647

3 0
2 years ago
There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co
mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

q_1=q_2=2.06\mu C=2.06\times 10^{-6} C

q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force,F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2

F_1=F_3=F

F_{net}=\sqrt{F^2+F^2+0}-F_2

F_{net}=\sqrt 2F-F_2

F=\frac{kq^2}{d^2}

F_2=\frac{Kq^2}{2d^2}

F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})

Where k=9\times 10^9

F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})

F_{net}=0.208 N

3 0
3 years ago
What type of lamp is used in a spectrophotometer to produce visible light?
avanturin [10]

Answer:

Visible, or infrared lights

3 0
3 years ago
An energetic child runs forward and backward. It's motion is shown on the following graph of horizontal position x vs time t
Klio2033 [76]

Answer: 0.50 m/s

Explanation: it’s on khan academy this was the correct answer

6 0
3 years ago
1. (I) If the magnetic field in a traveling EM wave has a peak magnitude of 17.5 nT at a given point, what is the peak magnitude
Elan Coil [88]

Answer:

The electric field is E  =  5.25 V/m

Explanation:

From the question we are told that

    The peak magnitude of the magnetic field is  B  =  17.5 nT  =  17.5 *10^{-9}\ T

Generally the peak magnitude of the electric field is mathematically represented as

         E  =  c  *  B

Where c is the speed of light with value c  =  3.0 *10^{8} \ m/s

So

       E  =  3.0 *10^{8}  *  17.5 *10^{-9}

       E  =  5.25 V/m

8 0
4 years ago
Other questions:
  • How energy is transferred in a appliance
    6·1 answer
  • V391 Pegasi b is a star that is 4,570 light years away from Earth. What is this distance in kilometers? (One light year is about
    5·2 answers
  • Electromagnetic induction occurs only when the current in the primary coil is constant. true or false
    7·1 answer
  • The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
    14·1 answer
  • What is the magnitude of the force excepted by the mass on the spring scale?
    10·1 answer
  • What is similar about the energy changes in the two reactions?
    10·2 answers
  • A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity
    15·2 answers
  • An airplane is traveling from North Africa to England. Which arrow correctly shows the direction gravity pulls the plane?
    6·1 answer
  • When the temperature of aid in a hot air balloon increases, what happens to the volume of gas?
    5·1 answer
  • A block of ice is sliding down a ramp of slope 40 to the horizontal. What is the rate of acceleration of the block? Assume the f
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!