Answer:
v = 1,167 10³ m / s
Explanation:
The equation for heat is
Q = m ce ΔT
Let's replace
Q = m 450 (1811-298)
Q = m 6.81 105
This is the energy of the ball, using energy conservation
Q = Me = K = ½ m v²
m 6.81 10⁵ = ½ m v²
v = √ (2 6.81 105)
v = 1,167 10³ m / s
This speed is greater than the speed of sound, so the process is unlikely to occur
Answer:
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Explanation:
Answer:
a= 1.59 m/s² : Magnitude of the acceleration
β = 65.22° (north of east) : Direction of the acceleration
Explanation:
Conceptual analysis
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
The acceleration is presented in the direction of the resultant force applied .
Calculation of the resultant forces (R)


R= 429.5 N
We apply the formula (1) to calculate the magnitude of the acceleration(a) :
∑F = m*a , m= 270 kg
R= m*a
429.5 =270*a

a= 1.59 m/s²
Calculation of the direction of the acceleration (β)


β = 65.22° (north of east)
The magnetic force acting on a charged particle moving perpendicular to the field is:
= qvB
is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.
The centripetal force acting on a particle moving in a circular path is:
= mv²/r
is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.
If the magnetic force is acting as the centripetal force, set
equal to
and solve for B:
qvB = mv²/r
B = mv/(qr)
Given values:
m = 1.67×10⁻²⁷kg (proton mass)
v = 7.50×10⁷m/s
q = 1.60×10⁻¹⁹C (proton charge)
r = 0.800m
Plug these values in and solve for B:
B = (1.67×10⁻²⁷)(7.50×10⁷)/(1.60×10⁻¹⁹×0.800)
B = 0.979T
Answer;
= -2.18 × 10^-5 C
Explanation;
m = 1.49 × 10^-3 kg
Take downward direction as positive.
Fg = m g
E = 670 N/C
Fe = q E
Fe + Fg = 0
q E + m g = 0
q = -m g/E
= -1.49 × 10^-3 × 9.81/670
= -2.18 × 10^-5 C
= -2.18 × 10^-5 C