**Answer:**

v = 1,167 10³ m / s

**Explanation:**

The equation for heat is

Q = m ce ΔT

Let's replace

Q = m 450 (1811-298)

Q = m 6.81 105

This is the energy of the ball, using energy conservation

Q = Me = K = ½ m v²

m 6.81 10⁵ = ½ m v²

v = √ (2 6.81 105)

v = 1,167 10³ m / s

This speed is greater than the speed of sound, so the process is unlikely to occur

**Answer:**

i think you need to show a picture

**Explanation:**

**Answer:**

**a= 1.59 m/s² : **Magnitude of the acceleration

**β = 65.22° (north of east) : **Direction of the acceleration

**Explanation:**

**Conceptual analysis**

We apply Newton's second law:

∑F = m*a** (Formula 1)**

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

**Problem development**

The acceleration is presented in the direction of the resultant force applied .

**Calculation of the resultant forces (R)**

**R= 429.5 N**

We apply the formula (1) to calculate **the magnitude of the acceleration(a) :**

**∑F = m*a ** , m= 270 kg

R= m*a

429.5 =270*a

**a= 1.59 m/s²**

**Calculation of the direction of the acceleration (β)**

**β = 65.22° (north of east)**

The magnetic force acting on a charged particle moving perpendicular to the field is:

= qvB

is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.

The centripetal force acting on a particle moving in a circular path is:

= mv²/r

is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.

If the magnetic force is acting as the centripetal force, set equal to and solve for B:

qvB = mv²/r

B = mv/(qr)

Given values:

m = 1.67×10⁻²⁷kg (proton mass)

v = 7.50×10⁷m/s

q = 1.60×10⁻¹⁹C (proton charge)

r = 0.800m

Plug these values in and solve for B:

B = (1.67×10⁻²⁷)(7.50×10⁷)/(1.60×10⁻¹⁹×0.800)

**B = 0.979T**

**Answer**;

= -2.18 × 10^-5 C

**Explanation**;

m = 1.49 × 10^-3 kg

Take downward direction as positive.

Fg = m g

E = 670 N/C

Fe = q E

Fe + Fg = 0

q E + m g = 0

q = -m g/E

= -1.49 × 10^-3 × 9.81/670

= -2.18 × 10^-5 C

**= -2.18 × 10^-5 C **