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3 years ago

13. What bone runs parallel to the fibula? A. Radius B. Femur C. Tibia D. Ulna

Physics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

C, Tibia.

The tibia is located down in the lower leg. Heres what it looks like.

i hope this helped at all.

BigorU [14]3 years ago

3 0

Answer:

C. Tibia :)

Explanation:

The fibula is the long, thin bone of the lower leg. It runs parallel to the tibia (aka shin bone) and plays a role in stabilizing the ankle and supporting the muscles of the lower leg

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if a sea star egg is taken from the ocean and put into Elk Lake would you expect the egg to shrink swell are stay the same ?

mafiozo [28]

It would swell

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3 years ago

Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit,

kodGreya [7K]

This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.

The height of the hill is "166.76 m".

<h3>LAW OF CONSERVATION OF ENERGY:</h3>

According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

$Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\
\frac{1}{2}mv_{max}^2=mgh\\\\
h=\frac{v_{max}^2}{2g}$

where,

h = height of the hill = ?

$v_{max}$ = maximum velocity = 57.2 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\
$

Learn more about the law of conservation of energy here:

brainly.com/question/101125

7 0

3 years ago

A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg

solong [7]

The mass of the large truck is determined as 5680 kg.

<h3>Mass of the truck</h3>

The mass of the truck is calculated as follows;

P = mv

where;

P is momentum
m is mass
v is velocity

m = P/v

m = 125000/22

m = 5680 kg

Thus, the mass of the large truck is determined as 5680 kg.

Learn more about momentum here: brainly.com/question/7538238

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7 0

2 years ago

ANOTHER PHYSICS QUESTION PLEASE HELP!

Sergio039 [100]

Answer

= 60

Hope it helps:)

5 0

3 years ago

g A lighter ball A with momentum PA=5.0 kg∙m/s in positive x-direction approaches a heavier ball B at rest before the collision.

Svet_ta [14]

Answer:

7kgm/s

Explanation:

Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Let P1A and P1B be the initial momentum of the bodies A and B respectively

Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.

Based on the law:

P1A+P2A = P1B + P2B

Given P1A = 5kgm/s

P2A = 0kgm/s(ball B at rest before collision)

P2A = -2.0kgm/s (negative because it moves in the negative x direction)

P2B = ?

Substituting the values in the equation gives;

5+0 = -2+P2B

5+2 = P2B

P2B = 7kgm/s

3 0

3 years ago