If it is the same vehicle, then the 60mph vehicle has more kinetic energy since it is moving faster. Therefore, it requires more energy to stop, and if it is the same car with the same beak system, the braking distance of the 30mph car will be significantly shorter than the 60mph car.
We know V=IR (Ohm's law).
We are given R=180Ω and I=0.1A, then V=(0.1AΩ)(180Ω). Therefore
V=18V
Answer:0kgm/s
Explanation:
Momentum before collision=momentum after collision
Since the momentum of the two blocks have positive sign, it means they are moving in thesame direction
Therefore we use the formula
Momentum (A)+momentum (B)=Momentum (A)+momentum (B)
25+35=60+momentum (B)
60=60+momentum (B)
Momentum (B)=60-60
Momentum (B)=0kgm/s
Answer:
The force required to push to stop the car is 288.67 N
Explanation:
Given that
Mass of the car, m = 1000 kg
Initial speed of the car, u = 1 m/s
The car and push on the hood at an angle of 30° below horizontal, 
Distance, d = 2 m
Let F is the force must you push to stop the car.
According work energy theorem theorem, the work done is equal to the change in kinetic energy as :
The force required to push to stop the car is 288.67 N
Answer:
C. Both technicians A and B
Explanation:
Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.
