Question

Determine the percent composition of chlorine (Cl) in sodium chloride (NaCl). .

Answer 1

It's (grams-of-Cl/total-grams)(100), so (35.45g/58.44g)(100) = 60.66% Cl. Hope this helps!

Answer 2

Answer:

$\% Cl=61.65\%$

Explanation:

Hello,

In this case, chlorine's percent composition is given by the shown below formula:

$\% Cl=\frac{n_{Cl}m_{Cl}}{M_{NaCl}}*100\%$

Whereas $n_{Cl}$ accounts for the number of chlorine atoms into the NaCl, $m_{Cl}$ for chlorine's atomic mass and $M_{NaCl}$ for sodium chloride's molar mass, therefore, the percent composition of chlorine turns out:

$\% Cl=\frac{1*35.45}{58.45}*100\%=61.65\%$

Best regards.