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ivanzaharov [21]
2 years ago
6

Determine the percent composition of chlorine (Cl) in sodium chloride (NaCl). .

Chemistry
2 answers:
faust18 [17]2 years ago
8 0
It's (grams-of-Cl/total-grams)(100), so (35.45g/58.44g)(100) = 60.66% Cl. Hope this helps!
Ronch [10]2 years ago
8 0

Answer:

\% Cl=61.65\%

Explanation:

Hello,

In this case, chlorine's percent composition is given by the shown below formula:

\% Cl=\frac{n_{Cl}m_{Cl}}{M_{NaCl}}*100\%

Whereas n_{Cl} accounts for the number of chlorine atoms into the NaCl, m_{Cl} for chlorine's atomic mass and M_{NaCl} for sodium chloride's molar mass, therefore, the percent composition of chlorine turns out:

\% Cl=\frac{1*35.45}{58.45}*100\%=61.65\%

Best regards.

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Source https://www.physicsforums.com/threads/calorimetry-help-chemistry.399653/
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