consider the forward direction as positive and backward direction as negative. hence displacement in froward direction will be taken as positive and displacement in backward direction will be taken as negative.
= displacement in forward direction = 10 meters
= displacement in backward direction = - 5 meters
= net displacement
net displacement is given as
=
+
= 10 + (- 5)
= 5 meters
Since net displacement is positive , and forward is positive direction of motion.
hence the displacement is 5 meters in forward direction.
b)
d₁ = distance traveled in forward direction = 10 meters
d₂ = distance traveled in backward direction = 5 meters
D = total distance traveled
total distance traveled is given as
D = d₁ + d₂
D = 10 + 5
D = 15 meters