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vazorg [7]
3 years ago
5

When very electronegative atoms, like oxygen, bond to atoms with lower electronegativity, like lithium, what's the result?

Physics
1 answer:
umka2103 [35]3 years ago
3 0

(A) The oxygen atom becomes strongly negative.

Explanation:

When a very electronegative atom like oxygen bonds to an atom with a lower electronegativity, like lithium, the oxygen atom becomes strongly negative and the lithium becomes strongly positive.

The attraction between these oppositely charged ions results in the formation ionic bond.

  • An ionic bond is an interatomic bond in which a highly electronegative atom is bonded to less electronegative one.
  • The electronegative nature of the oxgyen allows is to gain the electrons lost by weakly electronegative lthium.
  • Most metals have low electronegativity.
  • They then both will form ions.
  • The attraction between the oppositely charged ions results in an ionic/electrovalent bonding.

learn more:

Ionic bond brainly.com/question/6071838

#learnwithBrainly

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Hello! :)

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Because the sun’s heat makes the water turn to steam—or what we call “water vapor.”

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PLEASE HURRY 20 PTS
Crank

Answer:

A. The electric field points to the left because the force on a negative charge is opposite to the direction of the field.

Explanation:

The electric force exerted on a charge by an electric field is given by:

where

F is the force

q is the charge

E is the electric field

We see that if the charge is negative, q contains a negative sign, so the force F and the electric field E will have opposite signs (which means they have opposite directions). This is due to the fact that the direction of the lines of an electric field shows the direction of the electric force experienced by a positive charge in that electric field: therefore, a negative charge will experience a force into opposite direction.

5 0
3 years ago
A(n) 12500 lb railroad car traveling at 7.8 ft/s couples with a stationary car of 7430 lb. The acceleration of gravity is 32 ft/
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To solve this problem we will apply the concepts related to the conservation of momentum. That is, the final momentum must be the same final momentum. And in each state, the momentum will be the sum of the product between the mass and the velocity of each object, then

\text{Initial Momentum} = \text{Final Momentum}

m_1u_1 +m_2u_2 = m_1v_1+m_2v_2

Here,

m_{1,2}= Mass of each object

u_{1,2}= Initial velocity of each object

v_{1,2}= Final velocity of each object

When they position the final velocities of the bodies it is the same and the car is stationary then,

m_2u_2 = (m_1+m_2)v_f

Rearranging to find the final velocity

v_f = \frac{m_2u_2}{ (m_1+m_2)}

v_f = \frac{ 12500*7.8}{ 12500+7430}

v_f = 4.8921ft/s

The expression for the impulse received by the first car is

I = m_1 (v-u)

I = \frac{W}{g} (v-u)

Replacing,

I = \frac{12500}{32.2}(4.89-7.8)

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Contact between the bodies

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