Fair enough, but you'll have to tell us the volume of the bar first.
The linear velocity of a rotating object is the product of the angular velocity and the radius of the circular motion. Angular velocity is the rate of the change of angular displacement of a body that is in a circular motion. It is a vector quantity so it consists of a magnitude and direction. From the problem, the angular velocity is 5.9 rad per second and the radius is given as 12 centimeters. We calculate as follows:
Linear velocity = angular velocity (radius)
Linear velocity = 5.9 (12 ) = 70.8 cm / s
The linear velocity of the body in motion is 70.8 centimeters per second or 0.708 meters per second.
Answer:
Temperature of water leaving the radiator = 160°F
Explanation:
Heat released = (ṁcΔT)
Heat released = 20000 btu/hr = 5861.42 W
ṁ = mass flowrate = density × volumetric flow rate
Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³
ṁ = 1000 × 0.000126 = 0.126 kg/s
c = specific heat capacity for water = 4200 J/kg.K
H = ṁcΔT = 5861.42
ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C
And in change in temperature terms,
10°C= 18°F
11.08°C = 11.08 × 18/10 = 20°F
ΔT = T₁ - T₂
20 = 180 - T₂
T₂ = 160°F
Answer:
B. 59 kg
Explanation:
From the graph you notice that a linear relation in indicated by the line joining the points such that the points on the line represent the data that show a correct relationship in the experiment.
This means that the point outside the line has an error .
This point is the value 59 kg that does not align with other values which are included in the graph.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
The matter in gaseous state can be expanded to occupy the volumes of the container.
<h3>
Volume of each of the container</h3>
The volume of each of the container is calculated as follows;
<h3>Volume of the rectangular container</h3>
V = 5 in x 6 in x 3 in
V = 90 in³
<h3>Volume of the cylindrical container</h3>
V = πr²h
V = (π)(2.5 in)²(8 in)
V = 157.1 in³
<h3>Volume of the matter</h3>
Vm = 3 in x 4 in x 5 in
Vm = 60 in³
<h3>Matter in solid and liquid state</h3>
Matter has fixed volume in solid and liquid state.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
<h3>Matter in gaseous state</h3>
Matter has no definite volume in gaseous state.
The matter in gaseous state can be expanded to occupy the volumes of the container.
Learn more about states of matter here:
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