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vazorg [7]
4 years ago
5

When very electronegative atoms, like oxygen, bond to atoms with lower electronegativity, like lithium, what's the result?

Physics
1 answer:
umka2103 [35]4 years ago
3 0

(A) The oxygen atom becomes strongly negative.

Explanation:

When a very electronegative atom like oxygen bonds to an atom with a lower electronegativity, like lithium, the oxygen atom becomes strongly negative and the lithium becomes strongly positive.

The attraction between these oppositely charged ions results in the formation ionic bond.

  • An ionic bond is an interatomic bond in which a highly electronegative atom is bonded to less electronegative one.
  • The electronegative nature of the oxgyen allows is to gain the electrons lost by weakly electronegative lthium.
  • Most metals have low electronegativity.
  • They then both will form ions.
  • The attraction between the oppositely charged ions results in an ionic/electrovalent bonding.

learn more:

Ionic bond brainly.com/question/6071838

#learnwithBrainly

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The rectangular plates in a parallel-plate capacitor are 0.063 m x 5.4 m. A distance of 3.5 x 10^-5m separate the plates. The pl
Aleks04 [339]

The capacitance of the capacitor is 1.8\cdot 10^{-9}F

Explanation:

The capacitance of a parallel-plate capacitor is given by the equation

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the medium

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.1 is the dielectric constant

d=3.5\cdot 10^{-5}m is the separation between the plates

A=0.063m \cdot 0.054m = 0.0034 m^2 (I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)

Therefore, the capacitance of the  capacitor is

C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F

Learn more about capacitors:

brainly.com/question/10427437

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Answer:

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(b) The average force is:

F=\frac{J}{\Delta t}\\F=\frac{176.4\frac{kg*m}{s}}{0.083s}\\F=2125.30N

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