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stellarik [79]
3 years ago
10

A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below t

his line if it has been traveling for 1 s?
Physics
1 answer:
maria [59]3 years ago
4 0

Answer:

Explanation:

Suppose v is the initial velocity and \theta is the angle of inclination

distance traveled in vertical direction in t=1 s

When gravity is present

y=vt+\frac{1}{2}at^2

where y=vertical\ distance

a=acceleration

t=time

v=initial\ velocity

here initial velocity is v\sin \theta [/tex] so

y=v\sin \theta \times 1-\frac{1}{2}gt^2

y=v\sin \theta -0.5g

In absence of gravity

y_2=v\sin \theta \times t

y_2=v\sin \theta \times 1

\Delta y=y_2-y=v\sin \theta -v\sin \theta +0.5 g=4.9\ m

         

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The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
lesya [120]

Answer:

a) For P: v=0.938\frac{m}{s}

For Q: v = 1.876\frac{m}{s}

b) For P:

a_{rad}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}=17.60\frac{m}{s^{2}}

c) As the distance from the axis increases then speed increases too.

Explanation:

a) Assuming constant angular acceleration we can find the angular speed of the wheel dividing the angular displacement θ between time of rotation:

\omega =\frac{\theta}{t}

One rotation is 360 degrees or 2π radians, so θ=2π

\omega =\frac{2\pi}{0.670} =9.38\frac{rad}{s}

Angular acceleration is at every point on the wheel, but speed (tangential speed) is different and depends on the position (R) respect the rotation axis, the equation that relates angular speed and speed is:

v = \omega R

for P:

v = 9.38\frac{rad}{s}*0.1m=0.938\frac{m}{s}

for Q:

v = 9.38\frac{rad}{s}*0.2m=1.876\frac{m}{s}

b) Centripetal acceleration is:

a_{rad}= \frac{v^2}{R}

for P:

a_{rad}= \frac{(0.938)^2}{0.1}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}= \frac{(1.876)^2}{0.2}=17.60\frac{m}{s^{2}}

c) As seen on a) speed and distance from axis is v = \omega R because ω is constant the if R increases then v increases too.

3 0
3 years ago
Write the mathemetical relation between work force and displacement​
il63 [147K]

Answer:

Work is measured as the product of force and the displacement in the direction of the force. Work = force × displacement in the direction of the force.

8 0
2 years ago
Coulomb's law is expressed mathematically as
nataly862011 [7]
Force between two charges  = 

     ( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²

  in the direction away from each other.

In other words, if the force is positive, the charges are repelling.
If the force is negative, the charges are attracting.
4 0
3 years ago
7. Un bloque de 700 N se encuentra sobre una viga uniforme de 200 N y 6 m de longitud. El bloque está a una distancia de 1 m del
GrogVix [38]

Answer:

 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

Let's use trigonometry to decompose the tension

      sin 60 = T_{y} / T

      T_{y} = T sin 60

       cos 60 = Tₓ / T

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we apply the equation

       ∑ τ = 0

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the length of the bar is L = 6m

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let's calculate

let's use the maximum tension that resists the cable T = 900 N

             x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)

             x = (4676 - 5880) / 6860

             x = - 0.176 m

Therefore the block can be up to 0.176m to keep the system in balance.

5 0
3 years ago
How do you find the voltage of a section of a parallel circuit?
sergiy2304 [10]

Answer: Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source. You can find total resistance in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +.

Hope this helps!

3 0
3 years ago
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