Answer:
You're four sentences should include about how the roller coaster has the most potential energy at the top of the track, and the opposing energy, "kinetic" has the most kinetic energy when going down the hill.
Explanation:
Kinetic - In-Motion.
Potential - Gathering Energy to go into Motion.
( I'll try to answer questions to clear up confusion. )
Answer:
The velocity of the particle from T = 0 s to T = 4 s is;
0.5 m/s
Explanation:
The given parameters from the graph are;
The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m
The displacement covered at time, t₂ = 4 s is x₂ = 3 m
The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;
The velocity of the particle from t = 0 s to t = 4 s = 1/2 m/s = 0.5 m/s.
Answer:
80m/s
Explanation:
The formula for velocity is [ v = s/t ] where s = displacement and t = time.
= 400/5
= 80m/s
Best of Luck!
6: Short way: it cannot be 2.5, 3, or 5 because up to 5 seconds it only has positive velocity so it must be moving forwards.
Long Way: Velocity is in m / s, multiply that by time (s) to get m or displacement. From 0->5 you have a triangle under the curve, (1/2)(5)(20) = 50 meters displaced positive, you need to then look when velocity is under the curve and use a similar equation to solve for the area but make the answer negative. Find the point where it equals -50 and that is where it will have returned.
Answer to 6: B
7. I cannot see the problem enough to answer this. Just know if the line is above 0 velocity is positive so it is moving the direction it started, when it goes below 0 velocity is negative so it is moving opposite direction it started.
8. Accelration is change in velocity. Whatever the slope of the velocity graph is acceleration. At t=8 the slope is 0 because it is not going up or down.
Answer to 8: A
Answer:
Acceleration of the bullet while moving into the clay is -312500 ms⁻²
Explanation:
Given data
Initial velocity (v₁) = 250 m/s Final velocity (v₂) = 0 m/s
Distance (s)= 0.1 m acceleration (a) = ?
Using 3rd equation of motion
2as = v₂²- v₁²
2 × a × 0.1 = 0² - 250²
0.2 × a = -62500
a = -62500/0.2
a = -312500 m/s²
Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.