All categories

3 years ago

What is the number of Carbon atoms in 9.837 x 1024 molecules of CO2

Chemistry

1 answer:

Svet_ta [14]3 years ago

4 0

There is 1 carbon atom for every molecule of CO2 so it would be the same number:

$9.837 \times {10}^{24}$

You might be interested in

Tetrachloromethane,CC15,is classified as a

prohojiy [21]

Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.

7 0

4 years ago

What is the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b) halved when the temperature i

Alexxandr [17]

Answer:

a) 48KJ

b) -48KJ

Explanation:

Given that;

ln(K2/K1) = ΔH°/R(1/T2 - 1/T1)

K2= equilibrium constant at T2

K1 = equilibrum constant at T1

R = gas constant

T1 = initial temperature

T2 = final temperature

When we double the equilibrium constant K1; K2 = 2K1

T1 = 310 K

T2 = 310 + 15 = 325 K

ln(2K1/K1) =- ΔH°/R(1/T2 - 1/T1)

ln2 = -ΔH°/8.314(1/325 - 1/310)

0.693 = -ΔH°/8.314(3.08 * 10^-3 - 3.2 * 10^-3)

0.693 = -ΔH°/8.314 (-0.00012)

0.693 = 0.00012ΔH°/8.314

0.693 * 8.314 = 0.00012ΔH°

ΔH° = 0.693 * 8.314/0.00012

ΔH° = 48KJ

b) K2 =K1/2

ln(K1/2/K1) =- ΔH°/R(1/T2 - 1/T1)

ln (1/2) = -ΔH°/8.314 (1/325 - 1/310)

-0.693 = -ΔH°/8.314 (-0.00012)

-0.693 = 0.00012ΔH°/8.314

-0.693 * 8.314 = 0.00012ΔH°

ΔH°= -0.693 * 8.314/0.00012

ΔH°= -48KJ

6 0

3 years ago

The nucleus of the atom is held together by the mutual attraction of the positively charged protons and the negatively charged n

jek_recluse [69]

That is FALSE because neutrons have no charge and as their name suggest are neutral particles.

8 0

4 years ago

The coefficients in a chemical equation??

cricket20 [7]

D is the answer I believe.

3 0

3 years ago

Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) At 25°C, for this reaction,

insens350 [35]

Answer:

401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.

Explanation:

The expression for the standard change in free energy is:

$\Delta G=\Delta H-T\times \Delta S$

Where,

$\Delta G$ is the change in the Gibbs free energy.

T is the absolute temperature. (T in kelvins)

$\Delta H$ is the enthalpy change of the reaction.

$\Delta S$ is the change in entropy.

Given at:-

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25.0 + 273.15) K = 298.15 K

$\Delta H$ = 128.9 kJ/mol

$\Delta G$ = 33.1 kJ/mol

Applying in the above equation, we get as:-

$33.1=128.9-298.15\times \Delta S$

$-29815\Delta S=-9580$

$\Delta S=-9580$ = 0.32131 kJ/Kmol

So, For reaction to be spontaneous, $\Delta G$

Thus, For minimum temperature:-

$\Delta H-T\times \Delta S=0$

$128.9-T\times 0.32131=0$

$T=\frac{128.9}{0.32131}=401.17\ K$

<u>Hence, 401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.</u>

6 0

3 years ago