All categories

3 years ago

How many significant digits are in the volume measurement 0.010 mL? A) 1 B) 2 C) 3 D) 4 E) none of the above

Chemistry

1 answer:

fgiga [73]3 years ago

6 0

Answer:

The correct answer is option B.

Explanation:

Significant figures :These are figures in a number which expresses the value of the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Significant digits in the volume measurement 0.010 mL are:

$0.0\bar{10}$ = 2 significant figures

All non-zero numbers are always significant.
All zero’s preceding the first integers are never significant.
All zero’s after the decimal point are always significant.

You might be interested in

28. How many formula units are found in 0.250 moles of potassium nitrate?

Soloha48 [4]

Answer:

$\boxed {\boxed {\sf B. \ 1.5 *10^{23} \ formula \ units}}$

Explanation:

1 mole of any substance contains the same number of particles. The particles can vary (atoms, molecules, formula units), but there are always 6.022*10²³ particles. In this case, the particles are formula units of potassium nitrate or KNO₃.

Let's create a ratio.

$\frac {6.022*10^{23} \ formula \ units \ KNO_3}{1 \ mol \ KNO_3}$

Since we are trying to find the formula units in 0.250 moles, we multiply by that number.

$0.250 \ mol \ KNO_3 *\frac {6.022*10^{23} \ formula \ units \ KNO_3}{1 \ mol \ KNO_3}$

The units of moles of potassium nitrate cancel.

$0.250 *\frac {6.022*10^{23} \ formula \ units \ KNO_3}{1 }$

The denominator of 1 can be ignored, so we can make a simple multiplication problem.

$0.250 *{6.022*10^{23} \ formula \ units \ KNO_3}$

$1.5055 * 10^{23} \ formula \ units \ KNO_3$

If we round to the nearest tenth, the 0 in the hundredth place tells us to leave the 5 in the tenth place.

$1.5 *10^{23} \ formula \ units \ KNO_3$

0.250 moles of potassium nitrate is approximately equal to 1.5*10²³ formula units of potassium nitrate and choice B is correct.

7 0

2 years ago

Suggest 2 reasons why the noble gases become less ideal in their behaviour down the group from helium to xenon.

Elenna [48]

Reason1: electrons on farther layers become free easyer
2nd reason: volume of atoms grows (from Helium to Xeon) so instead of boyle-mariot law equation (PV=vRT) is more accurate to use van der walls equations that adds to the boyle-mariot equation the volume occupied by the atoms of the gas to the volume of the space between the atoms P(Vm-b)=vRT

4 0

3 years ago

A gas occupies 3.5L at 2.5 atm of pressure. What is the volume at 787 torr at the same temperature?

Kitty [74]

Answer: 8.45 L

Explanation:

Given that,

Initial volume (V1) = 3.5L

Initial pressure (P1) = 2.5 atm

[Since final pressure is given in torr, convert 2.5 atm to torr

If 1 atm = 760 torr

2.5 atm = 2.5 x 760 = 1900 torr

Final volume (V2) = ?

Final pressure (P2) = 787 torr

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

3.5L x 1900 torr = 787 torr x V2

6650L•torr = 787 torr•V2

Divide both sides by 787 torr

6650L•torr/787 torr = 787 torr•V2/787 torr

8.45 L = V2

Thus, the volume of the gas at 787 torr and at the same temperature is 8.45 Liters

5 0

3 years ago

What did GEM Anscombe stand for give a brief description?

KATRIN_1 [288]

Answer:

Explanation:

Anscombe is a philosopher who has approached contemporary themes, today enormously current, precisely in the ethical and social field, stimulating the development of virtue ethics as an alternative to utilitarianism, Kantian ethics and social contract theories. Anscombe argues that what we understand as a moral obligation, what we "must" do, is an obligation to God.

6 0

3 years ago

Which of the following statements is true?

k0ka [10]

The second and first one but if it isn’t 2 choices then 1

4 0

3 years ago