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3 years ago

Percentage composition

Chemistry

2 answers:

TiliK225 [7]3 years ago

3 0

There goes the ist of what you're supposed to do.

iogann1982 [59]3 years ago

3 0

Answer:

do your work and stay focused. It's been 4 years, hope you're doing well

Explanation:

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When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot

viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the $'n^{th}'$ orbit of hydrogen atom.

Formula used :

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

$E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV$

Energy of n = 2 in an hydrogen atom:

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV$

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

$E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV$

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

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3 years ago

Which metal was more reactive in water? How do you know?

Rom4ik [11]

Answer:

alkali metals

Explanation:

they all react vigorously or even explosively with cold water, resulting in the displacement of hydrogen.

6 0

3 years ago

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Determine the formula for iron l oxide

Elena L [17]

Fe2O is the formula for that

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3 years ago

in witch chamber does each state have the same number of votes, no matter how large or small its population?

ivolga24 [154]

The senate only allows two senates from each state.

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3 years ago

___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to

Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

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3 years ago