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Anit [1.1K]
3 years ago
14

Percentage composition

Chemistry
2 answers:
TiliK225 [7]3 years ago
3 0
There goes the ist of what you're supposed to do.

iogann1982 [59]3 years ago
3 0

Answer:

do your work and stay focused. It's been 4 years, hope you're doing well

Explanation:

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Argon atom can exist freely in nature, why​
lana [24]

Answer:

<em>Argon</em><em> </em><em>can</em><em> </em><em>exi</em><em>st</em><em> </em><em>freely</em><em> </em><em>in</em><em> </em><em>nature</em><em> </em><em>because</em><em> </em><em>it</em><em> </em><em>has</em><em> </em><em>a</em><em> </em><em>full</em><em> </em><em>octet</em><em> </em><em>of</em><em> </em><em>electron</em><em>s</em><em> </em><em>the</em><em> </em><em>way</em><em> </em><em>its</em><em> </em><em>found</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>nature</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>way</em><em> </em><em>its</em><em> </em><em>found</em><em> </em><em>in</em><em> </em><em>periodic </em><em>table</em><em> </em><em>of</em><em> </em><em>element </em><em>in</em><em> </em><em>vast</em><em> </em><em>amouts</em><em> </em><em>of</em><em> </em><em>stabilization</em><em>.</em>

7 0
3 years ago
At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
3 years ago
8. A sample of chloroform is found to contain 24.0 g of carbon,212.8 g of chlorine, and 2.02 g of hydrogen. If a second sample o
Misha Larkins [42]

Answer:

595.5

Explanation:

chloroform with 24.0 g C was 238.2 g

24g/238.2g= 60g/x

595.5

4 0
3 years ago
I need help with this question ASAP
avanturin [10]

Answer:

True

Explanation:

Asexual reproduction does not involve sex cells or fertilization . Only one parent is required, unlike sexual reproduction which needs two parents. As a result, the offspring are genetically identical to the parent and to each other.

7 0
3 years ago
How man grams of cl2 are consumed to produce 12.0 g of KCl
Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0
3 years ago
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