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Leona [35]
3 years ago
15

Which would most likely cause a person to produce antibodies?

Chemistry
2 answers:
rosijanka [135]3 years ago
7 0

Answer:

receiving a vaccination

Explanation:

Drupady [299]3 years ago
6 0

Answer:A is the answer to ur question

Explanation:

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when riding bumper cars at the fair you bump into your friend and your car bounces backwards which law of motion is this
weeeeeb [17]

Newton's third law of interaction, says that if one body exerts a force on a second body, the second body exerts a force equal in magnitude and opposite in direction on the first body. It's the law of action-reaction, and it helps to explain why you feel a jolt when you collide with another bumper car.

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In a system, supply and demand forces affect the production and consumption decisions. there is little to no control in such a s
Zinaida [17]

The correct answers are

Free enterprise      and      government

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8 0
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Read 2 more answers
Need help please help me
Mademuasel [1]

Answer:

The answer is most likely compound a

Explanation:

Covalent compounds have low melting and boiling points and conduct electricity poorly

8 0
3 years ago
_A1Br3+_K=_KBr+_A1<br> fill in the correct coefficients.
Nataly_w [17]
1 A1Br3 + 3 K = 3 KBr + 1 A1
3 0
3 years ago
HELPP
slamgirl [31]

Answer:

In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.

Explanation:

tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:

\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=

mass compound

mass H

×100%

\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=

mass compound

mass C

×100%

If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:

\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=

10.0g compound

2.5g H

×100%=25%

\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=

10.0g compound

7.5g C

×100%=75%

7 0
3 years ago
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