Answer:
4m/s
Explanation:
May be different considering how long the pole is and how heavy the firefighter is.
Answer:
The magnitude of the horizontal net force is 13244 N.
Explanation:
Given that,
Mass of car = 1400 kg
Speed = 17.7 m/s
Distance = 33.1 m
We need to calculate the acceleration
Using equation of motion

Where, u = initial velocity
v = final velocity
s = distance
Put the value in the equation



Negative sign shows the deceleration.
We need to calculate the net force
Using newton's formula



Negative sign shows the force is opposite the direction of the motion.
The magnitude of the force is

Hence, The magnitude of the horizontal net force is 13244 N.
and C. corrosive, increases the concentration of hydrogen ions when added to water, forms hydrogen gas when it comes in contact with a metal, and formssalt and water when added to a base.
68 degrees would be the answer
Answer:
the maximum is I₁ axis of rotation at the end
the minimum moment is I₂ axis of rotation at the center of mass
Explanation:
For this exercise we use the definition moment of inertia
I = ∫ r² dm
for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are
at one end
I₁ = ⅓ mL²
in in center
I₂ =
m L²
There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder
I₃ =
m r²
remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small
when examining the different moments of inertia:
the maximum is I₁ axis of rotation at the end
the minimum moment is I₂ axis of rotation at the center of mass