Answer:
v after 5s = 0.25 m/s, it took 10s to stop, it has traveled 2.5m before stopping
Explanation
We can use the equation of motion with constant acceleration
Given: v0= 0.5 m/s a= -0.05 m/s²
v(5s) = v0 + a×t = 0.25 m/s
Stop => v=0 => v0 + a×t = 0 => t=10s
Distance at t=10s ⇒ x(10) = 0.5×10 + 0.5x(-0.05)x10² = 2.5m
Answer:
No
Explanation:
The supplied information about the object and train is incomplete. Acceleration is the rate at which the velocity of a body changes with time. Here the velocity and time is not given
A) 300cm/h
B)1 hr=60 min
300/60=5
5cm/min
C)1m=100cm
300/100=3
3m/h
Answer: 7.41 m/s
Explanation: By using the law of of energy, kinetic energy of the brick as it falls equals the potential energy before falling.
Kinetic energy = mv²/2, potential energy = mgh
mv²/2 = mgh
v²/2 = gh
v² = 2gh
v = √2gh
Where g = 9.8 m/s², h = 2.80m
v = √2×9.8×2.8 = 7.41 m/s
