Answer:
See figure 1.
Explanation:
In this case have to take into account that <u>all structures</u> must have the formula: . If we remember the <u>general formula for alkanes</u>: if we have <u>"7" carbons (n=7)</u> we will have <u>16 hydrogens</u>. Therefore all the structures that fit with this formula are alkanes.
The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized
Answer:
So, when bromine comes near the ethylene pi bond, it <u><em>attacks the electron and grabs it</em></u>, but the second bromine steals it away and departs as Br-. After all, bromine is more electronegative than carbon; the first bromine is just a link in the chain of events that allows the second bromine to escape with an electron.
Sodium hydride has the formula NaH where we have a sodium ion, Na⁺ and a hydride ion, H⁻. Hydride is an incredibly powerful base. While it is capable of acting as a nucleophile, if there is an acidic proton in a molecule, the hydride will deprotonate the molecule and grab the most acidic proton.
The pka of H⁻ is 35. The pka of ethanol is 16. The species with the larger pka is the better base and is capable of deprotonating the species with the smaller pka. Therefore, the hydride will deprotonate the acidic -OH proton of the alcohol in the following reaction:
CH₃CH₂OH + NaH → CH₃CH₂O⁻Na⁺ + H₂
The result of the reaction is the hydride deprotonates the proton of the alcohol and forms the alkoxide, which is a sodium salt. This reaction also leads to the formation of H₂ gas which ensures that this reaction is not reversible as the H₂ leaves the reaction mixture upon formation.