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Arte-miy333 [17]
3 years ago
11

What level of nitrates is considered clean water?

Physics
1 answer:
lana66690 [7]3 years ago
6 0
The U.S. Environmental Protection Agency (EPA) standard for nitrate in drinking water is 10 milligrams of nitrate (measured as nitrogen) per liter of drinking water (mg/L). * Drinking water with levels of nitrate at or below 10 mg/L is considered safe for everyone.
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What can electromagnetic waves travel through?
Kisachek [45]
Electromagnetic waves do not require a medium to travel through. They can travel through empty space or matter.
6 0
3 years ago
A mass of gas under constant pressure occupies a volume of 0.5 m3 at a temperature of 20°C. Using the formula for cubic expansio
Kryger [21]
No cubic expansion given
6 0
3 years ago
Electronics and inhabitants of the International Space Station generate a significant amount of thermal energy that the station
katrin2010 [14]

Answer:

4462.0927 W

Explanation:

\epsilon = Emissivity of the panel = 1

\sigma = Stefan-Boltzmann constant = 5.67\times 10^{-8}\ W/m^2K^4

T = Temperature = (273.15+6)

Area of the panel is given by

A=2\times 1.8\times 3.6\\\Rightarrow A=12.96\ m^2

The power radiated is given by

P=\epsilon \sigma AT^4\\\Rightarrow P=1\times 5.67\times 10^{-8}\times 12.96\times (273.15+6)^4\\\Rightarrow P=4462.0927\ W

The power radiated from each panel is 4462.0927 W

5 0
3 years ago
a 252,000j of heat energy is required to heat 2kg water. if (CH2O=42000j/kgk.what is change in temperature ?​
navik [9.2K]

Answer:

theres an decrease in temperature because 252,000 is more than 42,000. so its colder and not as hot as 252,000.

Explanation:

4 0
2 years ago
A candy-filled piñata is hung from a tree for Elia's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Tonja
Klio2033 [76]

Answer: v = 0.6 m/s

Explanation: <u>Momentum</u> <u>Conservation</u> <u>Principle</u> states that for a collision between two objects in an isolated system, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.

Momentum is calculated as Q = m.v

For the piñata problem:

Q_{i}=Q_{f}

m_{p}v_{p}_{i}+m_{s}v_{s}_{i}=m_{p}v_{p}_{f}+m_{s}v_{s}_{f}

Before the collision, the piñata is not moving, so v_{p}_{i}=0.

After the collision, the stick stops, so v_{s}_{f}=0.

Rearraging, we have:

m_{s}v_{s}_{i}=m_{p}v_{p}_{f}

v_{p}_{f}=\frac{m_{s}v_{s}_{i}}{m_{p}}

Substituting:

v_{p}_{f}=\frac{(0.54)(4.8)}{(4.4)}

v_{p}_{f}= 0.6

Immediately after being cracked by the stick, the piñata has a swing speed of 0.6 m/s.

3 0
3 years ago
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