Answer:
a) 
b) 
c) 
d) 
e) 
&
f) 
Explanation:
From the question we are told that:
Stretch Length 
Mass 
Total stretch length
a)
Generally the equation for Force F on the spring is mathematically given by
b)Generally the equation for Max Velocity of Mass on the spring is mathematically given by
Where
A=Amplitude
And
Therefore
c)
Generally the equation for Max Acceleration of Mass on the spring is mathematically given by
d)
Generally the equation for Total mechanical energy of Mass on the spring is mathematically given by
e)
Generally the equation for the period T is mathematically given by
Generally the equation for the Frequency is mathematically given by
f)
Generally the Equation of time-dependent vertical position of the mass is mathematically given by
Where
'= signify order of differentiation
Answer:
840 cm
Explanation:
Note: A hydraulic press operate based on pascal's principle.
From pascal's principle
W₁/d₁ = W₂/d₂...................... Equation 1
Where W₁ and W₂ are the first and second weight, and d₁ and d₂ are the first and second diameter of the piston.
make d₁ the subject of the equation
d₁ = W₁×d₂/W₂................ Equation 2
Given: W₁ = 2100 kg, W₂ = 25 kg, d₂ = 10 cm = 0.1 m.
Substitute these values into equation 2
d₁ = 2100(0.1)/25
d₁ = 8.4 m
d₁ = 840 cm
Answer:
θ = 22.2
Explanation:
This is a diffraction exercise
a sin θ = m λ
The extension of the third zero is requested (m = 3)
They indicate the wavelength λ = 630 nm = 630 10⁻⁹ m and the width of the slit a = 5 10⁻⁶ m
sin θ = m λ / a
sin θ = 3 630 10⁻⁹ / 5 10⁻⁶
sin θ = 3.78 10⁻¹ = 0.378
θ = sin⁻¹ 0.378
to better see the result let's find the angle in radians
θ = 0.3876 rad
let's reduce to degrees
θ = 0.3876 rad (180º /π rad)
θ = 22.2º
Answer:
d = 68.18 m
Explanation:
Given that,
Initial velocity, u = 15 m/s
Finally it comes to stop, v = 0
Acceleration, a = -1.65 m/s²
Time, t = 2.5 s
We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :
So, the hayride will cover a distance of 68.18 m.
